All categories

2 years ago

What is 16.2 simplified (and 121 simplified to)

Mathematics

1 answer:

Cerrena [4.2K]2 years ago

7 0

Answer:

16.2 = $\frac{81}{5}$ and 121 = $\frac{121}{1}$

Step-by-step explanation:

16.2 can be simplified to its fraction form, which is $\frac{81}{5}$

$16+\frac{2}{10} =\frac{81}{5}$ which is 16.2

121 is already simplified since it is a whole number, but its fraction form would be $\frac{121}{1}$

$121+\frac{0}{10} =121$ which is 121

-----

<em>(I hope this helped & good luck! <3)</em>

You might be interested in

Which best explains what determines whether a number is irrational?

AleksandrR [38]

You can determine if a number is rational if it can be represented as a terminating or repeated decimal, but if it can not, then the number is irrational.

8 0

3 years ago

Find the constant of proportionality and the unit rate for the data table. Then write an equaion to represent the relationship b

Akimi4 [234]

$\dfrac{90}2=45$

$\dfrac{135}3=45$

$\dfrac{225}5=45$

$\dfrac{270}6=45$

The constant of proportionality is thus 45; the unit rate is 45 miles per hour.

The relationship between the time t (in hours) and the distance d (in miles) is thus $d=45\cdot t$

6 0

2 years ago

4-It has been a bad day for the market, with 70% of securities losing value. You are evaluating a portfolio of 20 securities and

riadik2000 [5.3K]

Answer:

b) 0.0007

c) 0.4163

d) 0.2375

Step-by-step explanation:

We are given the following:

We treat securities lose value as a success.

P(Security lose value) = 70% = 0.7

Then the securities lose value follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 20.

a) Assumptions

There are 20 independent trials.
Each trial have two possible outcome: security loose value or security does not lose value.
The probability for success of each trial is same, p = 0.7

b) P(all 20 securities lose value)

We have to evaluate:

$P(x = 20)\\= \binom{20}{0}(0.7)^0(1-0.7)^{20}\\= 0.0007$

0.0007 is the probability that all 20 securities lose value.

c) P(at least 15 of them lose value.)

$P(x \geq 15)\\= P(x=15) + P(x = 16) + P(x=17) + P(x=18) +P(x = 19) +P(x = 20)\\ \binom{20}{15}(0.7)^{15}(1-0.7)^{5} +...+ \binom{20}{20}(0.7)^{20}(1-0.7)^{0} \\=0.4163$