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Norma-Jean [14]

2 years ago

12

What is 16.2 simplified (and 121 simplified to)

1 answer:

Cerrena [4.2K]2 years ago

7 0

Answer:

16.2 = $\frac{81}{5}$ and 121 = $\frac{121}{1}$

Step-by-step explanation:

16.2 can be simplified to its fraction form, which is $\frac{81}{5}$

$16+\frac{2}{10} =\frac{81}{5}$ which is 16.2

121 is already simplified since it is a whole number, but its fraction form would be $\frac{121}{1}$

$121+\frac{0}{10} =121$ which is 121

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<em>(I hope this helped & good luck! <3)</em>

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Please help me with this!!

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Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the $x$ values in the table. In other words, we need to replace $x$ with each value in our given function and simplify.

- For x = 0

$f(x)=(x-2)^2-5$

$f(0)=(0-2)^2-5$

$f(0)=(-2)^2-5$

$f(0)=4-5$

$f(x)=-1$

Since $x=0$ and $y=-1$ , our first point is (0, -1)

- For x = 1

$f(x)=(x-2)^2-5$

$f(1)=(1-2)^2-5$

$f(1)=(-1)^2-5$

$f(1)=1-5$

$f(x)=-4$

Our second point is (1, -4)

- For x = 2

$f(x)=(x-2)^2-5$

$f(2)=(2-2)^2-5$

$f(2)=(0)^2-5$

$f(x)=-5$

Our third point is (2, -5)

- For x = 3

$f(x)=(x-2)^2-5$

$f(3)=(3-2)^2-5$

$f(3)=(1)^2-5$

$f(3)=1-5$

$f(x)=-4$

Our fourth point is (3, -4)

- For x = 4

$f(x)=(x-2)^2-5$

$f(4)=(4-2)^2-5$

$f(4)=(2)^2-5$

$f(4)=4-5$

$f(x)=-1$

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

3 0

2 years ago