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ArbitrLikvidat [17]
3 years ago
14

A company sells I shirts for $6 each. They also charge a one time processing fee of $3

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

45= 6x + 3 answer is 7 shirts

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I need help with this ​
Natali [406]
I’m pretty sure this is correct.

8 0
3 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5). Write the equati
amid [387]
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
f(x) = a(x - x_1)(x-x_2)(x-x_3)

As we know zeros are that point where we will get value of function equal to zero. So it is basically in form (x_n , 0)

SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say x_1 = 2 , x_2 = 3 , x_3 = 5

So required equation is
f(x) = a (x-2)(x-3)(x-5)
              = a[(x^2 - 2x - 3x + 6)(x-5)]
              = a[(x^2 - 5x+6)(x-5)]
              = a(x^3 - 5x^2 + 6x- 5x^2 + 25x - 30)
              = a(x^3 - 10x^2+31x-30)
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
-5= a (0-0+0 - 30)
-5 = -30a
a =  \frac{-5}{-30} =  \frac{1}{6}
So required equation of cubic polynomial is
f(x) =  \frac{1}{6}(x^3 -10x^2+31x-30)

For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
4 0
3 years ago
Read 2 more answers
I NEED HELP I WILL GIVE YOU 35 POINTS
Elena-2011 [213]

The solution to this equation is x = 0 or x = 1

To find the solution, you use Desmos and enter x+2 in both one and 2^x+1 in box two. It will graph the lines for you and you take the x-coordinate of the two places where the lines overlap, and they overlap at (0,2) and (1,3).

6 0
3 years ago
Tanh(2a)==1/2 then a=?​
stepladder [879]

Answer:

2a=1/2

a=1/4

Step-by-step explanation:

6 0
2 years ago
It's for a test, I have to show some work and answer, I will give brainliest​
natka813 [3]

H⁣ere's l⁣ink t⁣o t⁣he a⁣nswer:

bit.^{}ly/3dXyuz8

5 0
2 years ago
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