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maxonik [38]
4 years ago
5

Want Brainliest? Get this correct Which of the following is the quotient of the rational expressions shown below? Make sure your

answer is in reduced form.

Mathematics
1 answer:
elena-14-01-66 [18.8K]4 years ago
4 0

Answer:

B.

Step-by-step explanation:

First, notice that we can cancel out an x in the second term. Thus:

\frac{3x^2}{x^2+x} =\frac{3x^2}{x(x+1)} =\frac{3x}{x+1}

As with the last question, change the sign to multiplication and "flip" the second term:

\frac{2x-1}{x+1}\cdot \frac{x+1}{3x}

Multiply straight across:

=\frac{(2x-1)(x+1)}{(x+1)(3x)}

Cancel the (x+1) term:

=\frac{2x-1}{3x}

Cannot be simplified further.

B.

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It is 8.7cm just trust me bro I got it right
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Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
The graph of g(x)=(0.5)x+4 is shown. Which equation is an asymptote of this function? y = 0 y = 4 x = 4 x = 0
Alexandra [31]

we are given

g(x)=(0.5)^x+4

we can see that

there is no value of x for which g(x) is not defined

so, no vertical asymptote exists

now, we will find horizontal asymptote

\lim_{x \to \infty} g(x)= \lim_{x \to \infty}((0.5)^x+4 )

\lim_{x \to \infty} g(x)= (\lim_{x \to \infty} (0.5)^x+\lim_{x \to \infty} 4 )

\lim_{x \to \infty} g(x)= 0+4

so, we get

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y= 4............Answer

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mixas84 [53]

Answer:

3x × 7y + 9z

Step-by-step explanation:

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3 years ago
Find the smallest positive integer divisible by $10$, $11$, and $12$.
Leya [2.2K]

Answer:

Smallest divisible number = 660

Step-by-step explanation:

Given:

Numbers

10, 11, 12

Find:

Smallest divisible number

Computation:

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11 = 11×1

12 = 2×2×3

Smallest divisible number = 2×2×3×5×11

Smallest divisible number = 660

3 0
3 years ago
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