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2 years ago

Please help! Find the approximate location of the decimal form of 2/3 on the number line below

Mathematics

1 answer:

kirill115 [55]2 years ago

8 0

Answer:

Step-by-step explanation:

The answer would be C because 2/3 as a decimal is 0.6666 and it goes on forever. D is at 0.75 which is too big and a and b are less than 0.5, so C is the correct answer.

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Value of the pronumeral and describe the rule. 4,1,-2,p,-8,-11

Citrus2011 [14]

Answer:

p = -5

every element in the sequence is created by subtracting 3 from the pervious element.

Step-by-step explanation:

I am not sure you put every necessary information here.

but I'd the visible information is truly everything, then it's is trivial.

the difference between 4 and 1 is ... well, -3. meaning we subtract 3 from 4 to get 1.

we suspect this is the rule and keep trying.

1 -3 = -2

hey it works.

and -8 -3 = -11

hey, also correct.

and the difference between -2 and -8 is -6, and when we place another item in between (p), we cut that in half again to -3. so, it is all consistent.

therefore,

p = -2 -3 = -5

the rule is

an = an-1 - 3

6 0

2 years ago

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let A = boards have solder defects and B = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

3 years ago

HELP PLZ! I do not understand this!!

neonofarm [45]

PART 1
If I have graph f(x) then graph f(x + 1/3) would translate the graph 1/3 to the left.

For example, I have f(x) = x².Then
f(x + 1/3) = (x + 1/3)²

I draw the graph of f(x) = x² and the graph of f(x) = (x + 1/3)² on cartesian plane to know what's the difference between them.

PART 2
If I have graph f(x) then graph f(x) + 1/3 would translate the graph 1/3 upper.

For example, I have f(x) = x².Then
f(x) + 1/3 = x² + 1/3

I draw the graph of f(x) = x² and the graph of f(x) = x² + 1/3 on cartesian plane to know what's the difference between them.

SUMMARY
f(x+1/3) ⇒⇒ f(x) is translated 1/3 units left.
f(x) + 1/3 ⇒⇒ f(x) is translated 1/3 units up.