Answer:
H0 : μd = 0
H1 : μd ≠ 0
Test statistic = 0.6687 ;
Pvalue = 0.7482 ;
Fail to reject H0.
Step-by-step explanation:
H0 : μd = 0
H1 : μd ≠ 0
Given the data:
Before: 15 26 66 115 62 64
After: 16 24 42 80 78 73
Difference = -1 2 24 35 -18 -9
Mean difference, d ; Σd / n
d = Σx / n = ((-1) + 2 + 24 + 35 + (-18) + (-9))
d = Σx / n = 33 / 6 = 5.5
Test statistic = (d / std / sqrt(n))
std = sample standard deviation = 20.146
Test statistic = 5.5 ÷ (20.146/sqrt(6))
Test statistic = 0.6687
The Pvalue :
P(Z < 0.6687) = 0.7482
At α = 0.05
Pvalue > α ; Hence we fail to reject H0
The data does not suggest a significant mean difference in the average number of accidents after information was added to road signs.
Answer:
The correct option is 4.
Step-by-step explanation:
The given function is
![f(x)=-0.05x^2+2.5x+5.2](https://tex.z-dn.net/?f=f%28x%29%3D-0.05x%5E2%2B2.5x%2B5.2)
Where f(x) is height of the ball and x is the distance.
It is a polynomial function with degree 2. All polynomial functions are defined for all real numbers, therefore the mathematical domain of the function is all real numbers.
![-\infty](https://tex.z-dn.net/?f=-%5Cinfty%3Cx%3C%5Cinfty)
Factorize the given function.
![f(x)=-0.05(x^2-50x-104)](https://tex.z-dn.net/?f=f%28x%29%3D-0.05%28x%5E2-50x-104%29)
![f(x)=-0.05(x^2-50x-104)](https://tex.z-dn.net/?f=f%28x%29%3D-0.05%28x%5E2-50x-104%29)
![f(x)=-0.05(x^2-52x+2x-104)](https://tex.z-dn.net/?f=f%28x%29%3D-0.05%28x%5E2-52x%2B2x-104%29)
![f(x)=-0.05(x(x-52)+2(x-52))](https://tex.z-dn.net/?f=f%28x%29%3D-0.05%28x%28x-52%29%2B2%28x-52%29%29)
![f(x) = -0.05 (x - 52) (x + 2)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-0.05%20%28x%20-%2052%29%20%28x%20%2B%202%29)
Put f(x)=0 to find the x intercepts.
![0 = -0.05 (x - 52) (x + 2)](https://tex.z-dn.net/?f=0%20%3D%20-0.05%20%28x%20-%2052%29%20%28x%20%2B%202%29)
Equate each factor equal to 0.
![x=52,-2](https://tex.z-dn.net/?f=x%3D52%2C-2)
Therefore at x=52 and -2, the graph of f(x) intersects x-axis. Before x=-2 and after x=52 the values of f(x) is negative. Height cannot be negative, therefore reasonable domain is lie between -2 to 52.
Distance cannot be negative, therefore the reasonable domain must be positive.
![0\leq x\leq 52](https://tex.z-dn.net/?f=0%5Cleq%20x%5Cleq%2052)
Therefore the reasonable domain is
and option 4 is correct.
Answer:
d
Step-by-step explanation:
because it says in your thing up above to exchange but there is a 50% im wrong
Please explain more your question