Yes, it is possible. For example, let's say that point A is (0,4) and there's a reflection over the y-axis, then point A would still be (0,4).
Answer:
I think Its C
Step-by-step explanation:
I did it on unit test so idk if its right or wrong
Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.
Explanation:
(A)
From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).
If a shape rotate 90 degree counterclockwise about the origin, then,




Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).
(B)
If a figure reflect across the y-axis then,




Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).
Answer:

Step-by-step explanation:
![\displaystyle -[-3]^2 - [4(-3) - 9(-2)] + 6[-2] \hookrightarrow -9 - [-12 + 18] - 12 \hookrightarrow -9 - 6 - 12 \\ \\ \boxed{-27}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5B-3%5D%5E2%20-%20%5B4%28-3%29%20-%209%28-2%29%5D%20%2B%206%5B-2%5D%20%5Chookrightarrow%20-9%20-%20%5B-12%20%2B%2018%5D%20-%2012%20%5Chookrightarrow%20-9%20-%206%20-%2012%20%5C%5C%20%5C%5C%20%5Cboxed%7B-27%7D)
I am joyous to assist you at any time.
Answer:
Its answer C
Step-by-step explanation:
Can you tell me if it's right or not?