Answer:
Length = 10
Width = 13
Step-by-step explanation:
If the width of a rectangle is 3 units less than the length and if the area is 130 square units, the length is 10 units and the width is 13 units.
Formula: A=wl
Therefore, you have to find what two numbers multiply together in order to recieve 130 units.
A=wl=13·10=130
It's a big alphabet, why confuse us with N and n?
Anyway, this one is a bit easier than it looks. We're going to look at it mod 11, meaning we're only interested in the remainders when we divide by 11. The nice thing about multiplication and addition is if we're going to take the remainder at the end, we can also take the remainders at the beginning and along the way and get the same answer, with smaller numbers.
That all sounds very complicated. It's easier explained.
100 =9*11 +1 so has remainder 1 when divided by 11. So if we multiply by 100 that's not going to change the remainder when we divided by 11; it's like multiplying by 1.
So 100, 100^2, 100^3, etc all have remainder 1 when divided by 11. So we need to add up 11 of them to get a number that's divisible by 11.
Answer: 11
This is a form of the Pythagorean Theorem. We just need to know how far we went in the x direction and how far in the y direction then use
a^2 + b^2 = c^2 to find the value.
distance in the x direction (-4 to -4) that's easy it didn't move. so that is zero and thus would make the distance all in the y direction.
To move from 8 to -8 we take (8 - (-8)) = 8 + 8 = 16 which is your answer
Answer:
$5.55
Step-by-step explanation:
4.25 * 3.4 = $14.45
20 - 14.45 = $5.55
The answer is 10(t-1) (5t+3).
An algebraic equation of the second degree in x is a quadratic equation. Typically, a quadratic equation is expressed in standard form as,
.
And the factor is a number or algebraic expression that divides another number evenly without leaving any remainder.
To factor the given quadratic equation, first, take the common factor of the equation. Therefore,
Using the sum-product pattern, we can write 2t as 3t-5t. Therefore,
Now, find the common factor between the pairs within the bracket. We get,
Finally, rewriting the above terms by factoring out the greatest common factor, we get,
To know more about factoring quadratic equations:
brainly.com/question/1863222
