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____ [38]
3 years ago
15

If x = 3 and g= -6 than what is the value of 4x+3g

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0
4•3+3•-6=12-18=-6 so the answer will be -6
Veronika [31]3 years ago
5 0
Substitute 3 for x and -6 for g and solve 4(3)+3(-6)=-6
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Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

8 0
3 years ago
Chris bought 6 packages of napkins for his restaurant. there were 200 napkins in each packet. how many napkins did chris buy
IgorC [24]
It would be 1,200 napkins hope this helps
4 0
3 years ago
Read 2 more answers
What is the value of (-3)(5)(-4)?
Stells [14]

Answer:

60

Step-by-step explanation:

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In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt
ankoles [38]

Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

p_v =P(t_{(43)}>1.436)=0.079  

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

8 0
3 years ago
Need help ASAP don't send me links
Paha777 [63]

Answer:

36

Step-by-step explanation:

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2 years ago
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