Answer:
(0,2)
Step-by-step explanation:
the point where Oy intercepts the graph has x=0 and y= f(0)
so this is (0,2)
6x+3y=15
6*2+3y=15
12+3y=15
3y=3
y=1
6x+3y=15
6*5+3y=15
30+3y=15
3y=-15
y=-5
The answers is y=1 & -5
9514 1404 393
Answer:
2
Step-by-step explanation:
The products of chord lengths are the same for the intersecting chords:
AQ×BQ = CQ×DQ
6×12 = CQ×(38 -CQ)
This gives a quadratic in CQ:
CQ² -38CQ +72 = 0 . . . . . write in standard form
(CQ -2)(CQ -36) = 0 . . . . . factor the quadratic
CQ = 2 or 36 . . . . . . . values of CQ that make the factors zero
The minimum length of CQ is 2 units. (DQ will be 36.)
Answer:
10:40
Step-by-step explanation:
1+4=5
5=50
1=?
1×50÷5=10
5=50
4=?
4×50÷5=40
Answer =10:40
