Which of the following points are solutions to the equation y= -2/3x+2

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$y=-\dfrac{2}{3}x+2\\\\\left(-\dfrac{2}{5};\ \dfrac{34}{15}\right)\to x=-\dfrac{2}{5};\ y=\dfrac{34}{15}\\\\for\ x=-\dfrac{2}{5}\to y=-\dfrac{2}{3}\cdot\left(-\dfrac{2}{5}\right)+2=\dfrac{4}{15}+2=\dfrac{4}{15}+\dfrac{30}{15}=\dfrac{34}{15}\\CORRECT\\\\\left(\dfrac{7}{2};\ \dfrac{13}{3}\right)\to x=\dfrac{7}{2};\ y=\dfrac{13}{3}\\\\for\ x=\dfrac{7}{2}\to y=-\dfrac{2}{3}\cdot\dfrac{7}{2}+2=-\dfrac{7}{3}+2=-\dfrac{7}{3}+\dfrac{6}{3}=-\dfrac{1}{3}\neq\dfrac{13}{3}\\INCORRECT$

$\left(\dfrac{1}{8};\ \dfrac{23}{12}\right)\to x=\dfrac{1}{8};\ y=\dfrac{23}{12}\\\\for\ x=\dfrac{1}{8}\to y=-\dfrac{2}{3}\cdot\dfrac{1}{8}+2=-\dfrac{1}{12}+2=-\dfrac{1}{12}+\dfrac{24}{12}=\dfrac{23}{12}\\CORRECT\\\\\left(\dfrac{8}{3};\ \dfrac{2}{3}\right)\to x=\dfrac{8}{3};\ y=\dfrac{2}{3}\\\\for\ x=\dfrac{8}{3}\to y=-\dfrac{2}{3}\cdot\dfrac{8}{3}+2=-\dfrac{16}{9}+2=-\dfrac{16}{9}+\dfrac{18}{9}=\dfrac{2}{9}\neq\dfrac{2}{3}\\INCORRECT$