<h3>
Answer: 48</h3>
=====================================================
Explanation:
Triangle ABC is isosceles because AC = BC.
The angles opposite these congruent sides are angle ABC and angle BAC. These are the base angles.
For any isosceles triangle, the base angles are congruent.
Angle BAC = 69 degrees is given. So angle ABC = 69 as well.
-------------------
The missing angle must add to the two other angles so that all three angles in a triangle add to 180
(angle ABC) + (angle BAC) + (angle BCA) = 180
69 + 69 + (angle BCA) = 180
138 + (angle BCA) = 180
angle BCA = 180-138
angle BCA = 42
-------------------
Angle DCE is congruent to angle BCA because they are vertical angles.
Triangle DCE is a right triangle. The missing angle is 90-(angle BCA) = 90-42 = 48
angle EDC = 48 degrees
Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Total deposit = 645.30 + 645.30 = $1290.60
Total withdrawals= 158.25 +168.36+157.42+148.46 = $632.49
Balance = 398.26 + 1290.60 - 632.49 = $1056.37
Answer:
15 ft
Step-by-step explanation:
Hi, the illustration for the problem is a right triangle with:
hypotenuse (C)= the length of the ladder = L
horizontal side(A) = distance from bottom of the ladder to the building = L - 6
vertical side(B) = distance from the top of the ladder to the bottom of the building = L - 3
So, we can use Pythagoras formula:
A2 +B2= C2
(L – 6 )² + (L-3)² = L²
L²-12L+36+L²-6L+9 =L²
L2 -18L+45 =0
APPLYING QUADRATIC FORMULA WE OBTAIN:
L =15 OR L=3
If L=3
Vertical side = L-3 = 0 (Length can´t be 0)
So L=15
