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2 years ago

Which of the following values are in the domain of the function graphed

1 answer:

3 0

Answer: functions graphically because they were, after all, just sets of points in the plane. Then in ... However, of these two answers, only x = −2 fits in the domain x < 1 for this piece. This means the only x-intercept for the x < 1 region of the x-axis is (−2,0). ... use the formula f(x) = x − 3, so the point on the graph (1,f(1)) is (1,−2).

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Question 3-17 i really stink at math :( it just doesnt make sense to me. alsi im failing. plz help

Trava [24]

Answer:

Step-by-step explanation:

graph is a sad face, therefore a is negative. so 1 and 3 are out. the c is the y intercept, and the y intercept is at tye positve side. so 4 is the correct one.

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2 years ago

What is the least common multiple of 24, 16, and 32?

notsponge [240]

Answer: the LCM is 96

Step-by-step explanation: looked it up

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3 years ago

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Need help with number 3 inequalities with variables on both sides

Volgvan

Answer:

x ≤ 2

Step-by-step explanation:

We are given the inequality:

$\displaystyle{2x-3 \leq \dfrac{x}{2}}$

First, get rid of the denominator by multiplying both sides by 2:

$\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}$

Add both sides by 6 then subtract both sides by x:

$\displaystyle{4x-6+6 \leq x+6}\\\\\displaystyle{4x \leq x+6}\\\\\displaystyle{4x-x \leq x+6-x}\\\\\displaystyle{4x-x \leq 6}\\\\\displaystyle{3x \leq 6}$

Then divide both sides by 3:

$\displaystyle{\dfrac{3x}{3} \leq \dfrac{6}{3}}\\\\\displaystyle{x \leq 2}$

Therefore, the answer is x ≤ 2

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1 year ago

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Timed test please help. Can someone please help me explain how you graph the circle from the equation below and how you find the

ryzh [129]

Well, you have the radius and the center already. So all you have to do is graph the center point, then count from that center point out 5 units, then draw the circle.

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3 years ago

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(5w-2p)(3w+p-4) anyone one?

Elis [28]

The picture shows the answer
HOPE THIS HELPS!!

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2 years ago