The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Part a: subtract 48-30=18
Part b: i found it by subtracting 48 -30 because it says left over
Competition is most intense between closely related species that use the same resources, as both species are competing for these limited resources.
The Answer to the question is { }.<span>
This is because there are no answers that are odd and divisible by 2.</span>
Answer:
Point C
Step-by-step explanation:
We want to reflect across the x axis
That means the y coordinate changes sign
Z = ( 5 1/2 , 3)
Z' = ( 5 1/2 , -3)
That is point C
