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icang [17]
3 years ago
5

Distributive 8(4x+9)

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer: 32x + 72

Step-by-step explanation:

8*4x  +8*9

32x +72

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Instructions:Drag the tiles to the correct boxes to complete the pairs. Match each polynomial function with one of its factors.
Svetach [21]
We have the following functions:
 f (x) = x3 - 3x2 - 13x + 15
 f (x) = x4 + 3x3 - 8x2 + 5x - 25
 f (x) = x3 - 2x2 - x + 2
 f (x) = -x3 + 13x - 12
 Factoring we have:
 f (x) = x3 - 3x2 - 13x + 15 -------> x + 3
 
f (x) = x4 + 3x3 - 8x2 + 5x - 25 -> x + 5
 
f (x) = x3 - 2x2 - x + 2 ------------> x - 2
 
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4 years ago
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Solve the logarithmic equation for x.
aev [14]

Answer:

x = 2   or  x = 4

Step-by-step explanation:

Solve:   2 log x = log 2 + log(3x - 4)

log (x^2) =  log 2 + log (3x - 4)

log (x^2) = log [2*(3x - 4)]

x^2 =  2*(3x - 4)

x^2 = 6x - 8

x^2 - 6x + 8 = 0

factor:

(x - 2 )(x - 4) = 0

x = 2   or  x = 4

4 0
3 years ago
Help 80 points A concrete planter is formed from a square-based pyramid that was inverted and placed
Rufina [12.5K]

Answer:

<h3>(A)</h3>

The slant height of the pyramid refers to the height of a face of the pyramid.

Notice that each slant height forms a right triangle like the image attached shows, where the hypothenuse is the slant height. Additionally, the bottom leg is 1 yard, because is half of the base side, and the other leg is 2 yard. Using Pythagorean's Theorem, we have

h^{2} =1^{2} +2^{2} \\h=\sqrt{1+4}=\sqrt{5}

Therefore, the slant height is the square root of 5 yard.

<h3>(B)</h3>

The surface area of the composite figure is the sum of the surface area of both volumes.

<h3>Surface area of the cube.</h3>

S_{cube}=5(2yd)^{2}  =20 yd^{2}

Notice that we only included 5 faces of the cube, that is because the sixth is the base of the pyramid, so if we include it here, we would have the wrong total surface area.

<h3>Surface area of the pyramid.</h3>

S_{pyramid}=\frac{1}{2}pl

Where p is the perimeter of the base and l is the slant height.

S_{pyramid}=\frac{1}{2}(8yd)(\sqrt{5}yd )=4\sqrt{5}yd ^{2}

Therefore, the surface od the composite figure is

S_{total}=20yd^{2} +4\sqrt{5} yd^{2} \approx 29.94 yd^{2}

<h3>(C)</h3>

To find the cubic yards of concrete, we need to subtract the volume of the figures, because the concrete would be inside the space between the cube and the pyramid.

V_{concrete}=V_{cube}  -V_{pyramid}=l^{3}-  \frac{1}{3}l^{2}h

Where l=2yd and h=2yd

V_{concrete}=2^{3}-\frac{1}{3}(2)^{2} (2)=8-\frac{8}{3} \approx  5.33 yd^{3}

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3 years ago
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Bas_tet [7]
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3 years ago
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andrew-mc [135]

Answer:

25038x65

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I practic buy Using the common factor of this problem.

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