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Juliette [100K]
3 years ago
14

The birth weights (in kilograms) of 5 elephants, selected randomly, are 133, 120, 97, 106, 124 (Source: www.elephant.se). Below

are the summary statistics of the data and output from the analysis testing if the true average birth weight of the elephants is 100 kg.
min Q1 median Q3 max mean sd n missing
97 106 120 124 133 116 14.40 486 5 0
t = 2.4837, df = 4, p-value = 0.06794
alternative hypothesis: true mean is not equal to 100 95 percent confidence interval:
XXXXXX XXXXXX
What is the correct calculation of a 95% confidence interval for the true average birth weight of elephant?
(i) 116± 1.96 x 14.4
(ii) 116 ± 1.96 x 14.4/15
(iii)116 ±1.96 x 14.4/14
(iv) 116 ± 2.4837 x 14.4
(v) 116 ±2.4837 x 14.4/15
(vi) 116 ± 2.4837 14.4/74
(vii) 116 ± 2.78 x 14.4
(viii) 116 ± 2.78 x 14.4√5
(ix) 116 ±2.78 x 14.4√4
Mathematics
1 answer:
Alja [10]3 years ago
7 0

Answer:

(viii) 116 ± 2.78 x 14.4√5

Step-by-step explanation:

The given data is

Sample size =n= 5

Calculated t- value= 2.4837

Mean= 116

Standard deviation= sd= 14.40486

The t - value from table with 4 d.f for ∝/2 is  t∝/2 (n-1)= 2.776

The 95% confidence interval is calculated by

d` ± t∝/2 (n-1)  *sd/√n

Putting the values

116 ± 2.776* 14.40486/√5

Comparing these values with the options Part viii gives the best answer.

(viii) 116 ± 2.78 x 14.4√5

2.776 when rounded gives 2.78 and 14.40486 when  rounded gives 14.4

The rest are incorrect.

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The automobile assembly plant you manage has a Cobb-Douglas production function given by p = 10x^0.2 y^0.8
Zepler [3.9K]

Answer:

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

This value of Δy is not constant for a constant increase in production.

Step-by-step explanation:

We know that the production function is p = 10x^{0.2} y^{0.8}, and in the current situation p=1200 and x=130.

With this information we can calculate the actual budget level:

p_0 = 10x^{0.2} y^{0.8}\\\\1200=10*130^{0.2} y^{0.8}\\\\1200=26.47*y^{0.8}\\\\y=(1200/26.47)^{1/0.8}=45.33^{1.25}=117.62

The next year, with an increase in demand of 100 more automobiles, the production will be p_1=1300.

If we calculate y for this new situation, we have:

y_1=(\frac{p_1}{10x^{0.2}} )^{1.25}=(\frac{1300}{26.47} )^{1.25}=49.10^{1.25}=130

The budget for the following year is 130.

The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.

\Delta y=y_1-y_0=130.00-117.62=12.38

This value of Δy is not constant for a constant increase in production.

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Count the distance d, which gives you 7.

Use Pythogarean theorem to find c:
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NNADVOKAT [17]

Answer:

C.)

Step-by-step explanation:

The graph is positive this time, so right away you can eliminate A and B.

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