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belka [17]
3 years ago
5

21/50 divided by 21/34

Mathematics
2 answers:
motikmotik3 years ago
5 0
The answer would be 441/1700
Zinaida [17]3 years ago
3 0
The answer is:

<span><span>‌<span>25/17</span></span><span>‌</span></span>

Correct me if I'm wrong
Hope this helps:)
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1/6 time 3/7<br><br><br> Help I just get different answer
hodyreva [135]
1*3=3
6*7=42
3/42 can be simplifyed
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3 0
3 years ago
In ΔPQR, p = 95 inches, q = 64 inches and ∠R=53°. Find the area of ΔPQR, to the nearest square inch.
Elena L [17]
AREA = 2428

c= 76
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4 0
2 years ago
Read 2 more answers
Y = x – 6 x = –4 what is the solution to the system of equations? (–8, –4) (–4, –8) (–4, 4) (4, –4
fredd [130]

Answer:

(- 4, - 10 )

Step-by-step explanation:

Given the 2 equations

y = x - 6 → (1)

x = - 4 → (2)

Substitute x = - 4 into (1) for corresponding value of y

y = - 4 - 6 = - 10

Solution is (- 4, - 10 )

4 0
3 years ago
A roofer calculates his bid price using the formula P = 1.85s + 4.2f, where s is the area of the roof in square feet and f is th
solmaris [256]

Answer: 1,811 square foot

Step-by-step explanation:

Hi, to answer this question we have to solve the equation given, by substituting P = 4,148 and f=190 in the equation.

P = 1.85s + 4.2f

4,148 = 1.85s +4.2 (190)

Solving for s:

4,148 = 1.85s +798

4,148-798 =1.85s

3,350 = 1.85s

3,350/1.85 =s

s = 1,810.81 = 1,811 square foot  (rounded)

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
Read 2 more answers
Members of the millennial generation are continuing to be dependent on their parents (either living with or otherwise receiving
Morgarella [4.7K]

Answer:

a)

\bf H_0: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is 0.3

\bf H_a: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is greater than 0.3

b) 34%

c) practically 0

d) Reject the null hypothesis.

Step-by-step explanation:

a)

Since an individual aged 18 to 32 either continues to be dependent on their parents or not, this situation follows a Binomial Distribution and, according to the previous research, the probability p of “success” (depend on their parents) is 0.3 (30%) and the probability of failure q = 0.7

According to the sample, p seems to be 0.34 and q=0.66

To see if we can approximate this distribution with a Normal one, we must check that is not too skewed; this can be done by checking that np ≥ 5 and nq ≥ 5, where n is the sample size (400), which is evident.

<em>We can then, approximate our Binomial with a Normal </em>with mean

\bf np = 400*0.34 = 136

and standard deviation

\bf \sqrt{npq}=\sqrt{400*0.34*0.66}=9.4742

Since in the current research 136 out of 400 individuals (34%) showed to be continuing dependent on their parents:

\bf H_0: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is 0.3

\bf H_a: The mean of adults aged 18 to 32 that continue to be  dependent on their parents is greater than 0.3

So, this is a r<em>ight-tailed hypothesis testing. </em>

b)

According to the sample the proportion of "millennials" that are continuing to be dependent on their parents is 0.34 or 34%

c)

Our level of significance is 0.05, so we are looking for a value \bf Z^* such that the area under the Normal curve to the right of \bf Z^* is ≤ 0.05

This value can be found by using a table or the computer and is \bf Z^*= 1.645

<em>Applying the continuity correction factor (this should be done because we are approximating a discrete distribution (Binomial) with a continuous one (Normal)), we simply add 0.5 to this value and </em>

\bf Z^* corrected is 2.145

Now we compute the z-score corresponding to the sample

\bf z=\frac{\bar x -\mu}{s/\sqrt{n}}

where  

\bf \bar x= mean of the sample

\bf \mu= mean of the null hypothesis

s = standard deviation of the sample

n = size of the sample

The sample z-score is then  

\bf z=\frac{136 - 120}{9.4742/20}=16/0.47341=33.7759

The p-value provided by the sample data would be the area under the Normal curve to the left of 33.7759 which can be considered zero.

d)

Since the z-score provided by the sample falls far to the left of  \bf Z^* we should reject the null hypothesis and propose a new mean of 34%.

7 0
2 years ago
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