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Mashcka [7]
3 years ago
9

I need help- I’ll give brainlist if it’s right

Mathematics
2 answers:
Sav [38]3 years ago
5 0

Answer:

D. x > 4

Step-by-step explanation:

You have to do the opposite operations to get the variable on one side of the equation by itself.

4 - x + 4 = 8 - 4

x = 4

You only switch the comparison sign if you mutliply or divide by negative numbers when you do opposite operations to get the variable on one side of the equation by itself.

I hope this helps!

likoan [24]3 years ago
3 0

Answer:

D.  x>[4]

Plzzzzz give me Brainliest!!!!!  

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Which of the values shown are potential roots of f(x)=3x^3-13x^2-3x+45? Select all that apply
GrogVix [38]
<h3>f(x)=3x³-13x²-3x+45</h3><h3>f(x)=3x³-9x²-4x²+12x-15x+45</h3><h3>f(x)=3x²(x-3)-4x(x-3)-15(x-3)</h3><h3>f(x)=(x-3)(3x²-4x-15)</h3><h3>f(x)=(x-3)(x-3)(3x+5)</h3><h2>f(x)=(x-3)²(3x+5)</h2>

<h3><u>Roots:</u></h3><h3>x=3</h3><h3>x=-5/3</h3>
5 0
2 years ago
A rectangular flower bed covers an area of 11.76 square feet in the garden. The width of the flower bed is 3.5 feet less than it
Degger [83]
The length and width of the garden will be obtain as follows:
let the length be x ft, the width will be (x+3.5)ft
area of the bed will be:
A=length*width
11.76=x(x+3.5)
11.76=x^2+3.5x
thus
x^2+3.5x-11.76=0
solving this by quadratic formula we get:
x=[-b+/-sqrt(b^2-4ac)]/2a
thus plugging in the values we obtain
x=[-3.5+/-sqrt(3.5^2-4(-11.76*1))]/2
x=[-3.5+/-sqrt59.29]/2
x=[-3.5+/-7.7]/2
x=4.2 or -11.2
thus the length will be x=4.2 ft and the width will be x-3.5=0.7 ft
8 0
3 years ago
4. Find the value of x.<br> A) 6 √ 2<br> B) 12 √ 3<br> C) 24 √ 3<br> D) 12
Schach [20]
A^2+b^2=c^2
24^2=12^2+x^2
sqrt(576-144)=x
sqrt(432)=x
12sqrt(3)=x
the answer is c
7 0
2 years ago
Read 2 more answers
PLZ help me with this question
olga2289 [7]

Answer:

3

Step-by-step explanation:

3x4=12

its 3 because you need to find the balances so when you have 3 and you multiped my 4 you get 12 same as the other square.

3 0
2 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
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