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3 years ago

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

Mathematics

2 answers:

34kurt3 years ago

5 0

it is the last option C=5/9(F-32)

Tasya [4]3 years ago

4 0

Answer:

option (D) is correct.

formula that solves for C is $C=\frac{5(F-32)}{9}$

Step-by-step explanation:

Given : the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F as , $F=\frac{9}{5}C+32$

We have to find the correct formula that solve for C,

Consider the given formula,

$F=\frac{9}{5}C+32$

We have to find formula for C,

Thus, first subtract 32 both side, we get,

$F-32=\frac{9}{5}C$

Now, multiply 5 both side, we get,

$5(F-32)={9}C$

Now , divide both side by 9, we get,

$\frac{5(F-32)}{9}=C$

Thus, formula that solves for C is $C=\frac{5(F-32)}{9}$

Thus, option (D) is correct.

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2 years ago

Harrison ordered 6 cases of pickles for his restaurants. Each case contained p jars of pickles. Harrison delivered an equal numb

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B. 6p/7

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3 years ago

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Lapatulllka [165]

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3 years ago

Which is the equation of the line that has a slope of 3 and goes through the point (-3,-5)

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4 0

3 years ago

Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5

Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

<u>The student scores on this unit are:</u> 40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

Mean is calculated as;

Mean = $\frac{\sum X}{n}$

where $\sum X$ = Sum of all values in the data

n = Number of observations = 24

So, Mean = $\frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}$

= $\frac{1547}{24}$ = 64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.} }{2}$

= $\frac{62 + 62 }{2}$ = $\frac{124}{2}$ = 62

Hence, the median of the data is 62.

A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

The Range is calculated as the difference between the highest and lowest value in the data.

Range = Highest value - Lowest value

= 95 - 40 = 55

Hence, range of the data is 55.

5 0

3 years ago