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Stolb23 [73]
2 years ago
8

Find the length of side A

Mathematics
2 answers:
lilavasa [31]2 years ago
7 0

A) First option

Opposite - 2

Hypotenuse - a

OH - SOH

SIn(45) = 2/h

x h, then ÷ sin45

h = 2/sin45

h= 2 root 2

=2.83 to 2d.p

Or

Use Pythagoras Theorem to find a because b=2 as we're shown an isosceles triangle with those little dashes, on two side lengths.

Hope this helps!

Masteriza [31]2 years ago
6 0

Answer:

The answer you are looking for is

C. 5

Mark brainliest :)

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The ratio of black marbles to red marbles is 3:2. If there are a total of 25 marbles in a bag,
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Answer:

15 black marbles

Step-by-step explanation:

So its. A ratio (basically a fraction)

3/2

we add them up so we know how much marbles but not which kind

so we get 5

now we know for every 5 batches there is 3 black and 2 red

so we divide 25/5 to get 5

now we know there are 5, 5 batches of black ad red marbles.

now black is 3 of them so we multiply 5(3) which is 15

Now red is 2 of them so we multiply 5(2). Which is 10

now to check, if we add them up, they equal to 25 which is correct.

basically add the fraction, divide that by the original number, time the quotient by each number in the fraction.

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Answer: 91.5

Step-by-step explanation:

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Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

__

The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

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In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

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2 years ago
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