- Initial velocity=u=0m/s
- Distance=s=150m
- Time=t=10s
- Acceleration=a
Using second equation of kinematics






Using newtons second law



We know that
4 3/4---------> (4*4+3)/4----------> 19/4
1 1/10-----------> (10*1+1)/10----> 11/10
[pounds left]=[(19/4)-(11/10)-(2)]----> (10*19-4*11-40*2)/40
=(190-44-80)/40-------> 66/40---------> 1.65 pounds
1.65-----> 1 65/100--------> 1 13/20 pounds
the answer is 1.65 pounds (1 13/20 pounds)
Answer:
<em><u>SEE</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>IMAGE</u></em><em><u> </u></em><em><u>FOR</u></em><em><u> </u></em><em><u>ALL</u></em><em><u> </u></em><em><u>ANSWERS</u></em><em><u>.</u></em>
Answer: ![\sqrt[5]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%7D)
I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"
The rule I'm using is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
and the more general rule we could use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.
3x + 6 + 4 = 6 × 2 + 10
3x + 6 + 4 = 12 + 10
3x + 10 = 12 + 10
3x + 10 = 22
3x = 22 - 10
3x = 12
x = 12/3
x = 4
The answer is: x = 4.