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Svetradugi [14.3K]
4 years ago
7

In the diagram Shown a 2 foot wide flower border surrounds the heart shaped pond.What is the area of the border?

Mathematics
2 answers:
Dimas [21]4 years ago
8 0
This figure is what we would call a composite figure. A composite figure is a shape that is made up of multiple other shapes. when looking at the pond and the border that surrounds it, we can see that this heart shape is made up of two semi circles and a square. To find the area of the border, we will use the area formulas for semi circles and for squares: 

Semi Circle Area Formula: \pi  r^{2} ÷ 2
Square Area Formula: length x width 

Pi = 3.14 
Radius = Half of the diameter, in this case 6 

After finding the area of each shape, we can subtract the 2 ft width to find the area of the flower bed border. 
alukav5142 [94]4 years ago
4 0

Answer:

Area of the border is 142.80 ft²

Step-by-step explanation:

The given figure consist of three figures = 2× semicircles + 1 square.

We will calculate area of the figure including border

Area of one semicircle = (1/2)π×r²= (1/2)×π×(12/2)² = (1/2)π×(6)² = 18π ft²

Area of square = side² = 12² = 144 ft²

Total area = 144 + 18π + 18π = (144 + 36π) ft²

Now we will calculate area without border.

Area of the semicircle = (1/2)π×r² =(1/2)π×[(12-4)/2]²=(1/2)π×(4)² = 8π ft²

area of square = side²= (12-4)²= 8² = 64 ft²

Total area = 64 + 8π + 8π = (64 + 16π) ft²

Now the area of the border = Area with border - Area without border

= (144 + 36π) - (64 + 16π) = 20π + (144 - 64) = 20π + 80

= 20×3.14 + 80 = 142.80 ft²

Area of the border = 142.80 ft²

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Answer:

11.6666666667

Step-by-step explanation:

First you multiply 7 by 5

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There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
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Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

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Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

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k = ln(1/2)/8 = -0.0866

Then the function is:

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A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

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