Answer: F(x) = 5x^2 + 10x
The formula is
A=p (1-r)^t
A future value?
P present value 180
R rate of decreases 0.6
T time 2 years
A=180×(1−0.6)^(2)
A=180×(0.4)^(2)
A=28.8
A, D, and E are true
One X on the line plot marks one time something happened. So the two x’s above the 1 means that he practiced piano for one hour (see to the right that says hours next to the numbers, so 1=1 hour) two times.
45 minutes is 3/4 of an hour, and is the mark right between 1/2 and 1. There is one x above this mark, so that means Thaddeus practiced for 45 minutes one time, so B is false
Thadeus practiced piano for 30 minutes two times, so C is false because he didn’t mostly practice for thirty minutes.
D is correct because there are 2 Xs above the 0, which means two times he practiced for zero hours, which means he didn’t practice at all.
E is correct because 15 minutes is 1/4 of an hour, so it is the mark between 0 and 1/2. We see there are three x’s there, so that means he practiced for 15 minutes 3 times.
I hope this helps! Let me know if you want me to explain it differently.
The axis of symmetry for this parabola is the x-axis. The general form of the equation is:
4p(x-h) = (y-k)^2
where the focus has the coordinates of (h+p,k)
Manipulating the given equation to the general form:
4(1/3)(x-7)^2 = (y - 0)^2
Therefore the coordinates of the focus is:
(7+(1/3),0)
The answer is A.) (71/3,0)
Answer:
W = 15/4 ft . ib
Step-by-step explanation:
Force = 10ib
According to hooked law, f(x) = kx
x = 4inches = 4/12 ft
x= 1/3ft
f(x) = 1/3k
10 = 1/3k
k = 30 ib/ft
f(x) = 30x
Workdone = integral of f(x) with its limit
6 inches = 6/12 ft
= 1/2ft
W = integral(1/2 to 0) of 30x
W = 15x^2(1/2 to 0)
W = 15(1/2)^2 - 15(0)^2
W = 15(1/4) - 0
W = 15/4 ft. Ib