Answer:
hfjf fnnc v jud dbhj ejem emd jfbf
Step-by-step explanation:
The complete question in the attached figure
we have that
for c=5 and n=20------------> n*c=20*5=100
for c=2.5 and n=40------------> n*c=40*2.5=100
for c=2 and n=50------------> n*c=50*2=100
for c=1.25 and n=80------------> n*c=80*1.25=100
therefore
<span>the function that models the data is n*c=100
</span>
the answer is nc=100
The height of the tank must be at least 1 foot, or 12 inches. We know the floor area (which is length x width) must be at least 400 inches. Therefore these minimum dimensions already tell us that the minimum volume is 400 x 12 = 4800 cubic inches. Since we have a maximum of 5000 cubic inches, the volume must be within the range of 4800 - 5000 cubic inches.
We can set the height at exactly 1 ft (or 12 inches). Then we can select length and width that multiply to 400 square inches, for example, L = 40 inches and W = 10 in. This gives us a tank of dimensions 40 x 10 x 12 = 4800 cubic inches, which fits all the criteria.
Answer: The parking lot in the drawing is 36 centimeters.
Step-by-step explanation:
Given: Actual width of parking lot = 54 meters
The scale she used was 2 centimeters : 3 meters.
i.e. 3 actual meters = 2 centimeters on drawing
⇒ 1 actual meter =
centimeters on drawing
⇒ 54 actual meters =
centimeters on drawing
⇒ 54 actual meters = 36 centimeters
Hence, the parking lot in the drawing is 36 centimeters.