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KengaRu [80]
3 years ago
13

What is the area of a square with side length: 3cm

Mathematics
2 answers:
storchak [24]3 years ago
6 0
12cm :) the reason why it’s 12 is because a square has 4 sides so 3 by 4 is 12
ratelena [41]3 years ago
5 0

Answer:

Since every square has the same length in sizes...

3 x 3 = 9cm

Answer: 9cm

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Line a is parallel to line b, m 6=85 and m 3=2x. Find m 1.
FromTheMoon [43]
The sum of the angles <6 and <3 must be 180. Since <3 and <1 are opposed to the top, their measure are equal. We need then to calculate the measure of angle >3 = 180 - <6 = 180-85=95

m(<1) = 95 

8 0
3 years ago
Match the data to the summary 5,10,15,20,25,25,25,30,35,40,45,50
Serjik [45]
Minimum = 5
maximum = 50
Q1 = (15 + 20)/2 = 17.5
Q2 (median) is 25
Q3 = (35 + 40)/2 = 37.5
8 0
3 years ago
estimate 0.00792398 to the nearest thousandth. Express your answer as a single-digit times a power of ten
Marianna [84]

Answer: \approx8*10^{-3}

Step-by-step explanation:

In order to round to the nearest thousandth, you must observe the digit to the right of the digit in the thousandth place and then:

  • If it is less than 5, you must round down.
  • If it is greater than or equal than 5, you must round up.

In this case, given the number:

0.00792398

You can notice that the digit to the right of the digit in the thousandth place is 9.

Since 9>5, you must round up. Then:

0.00792398\approx0.008

Finally, to express this as a single-digit times a power of ten, move the decimal point three places to the right. Then you get:

\approx8*10^{-3}

5 0
3 years ago
23 points please help simplify the square root sqrt (32x^2) if x&gt;=0
dexar [7]

Answer:

4√2x.

Step-by-step explanation:

√32 = √2*√16 = 4√2.

√x^2 = x.

3 0
2 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
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