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Virty [35]
3 years ago
14

Is ∆JKL ≅ ∆KJM ? Justify your answer below.

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

∠JLK = ∠KMJ

LK = MJ

∠LKJ = ∠MJK

∆JKL ≅ ∆KJM     {Angle side Angle - ASA congruence}

makkiz [27]3 years ago
4 0

Answer:

Yes, the triangles are congruent by ASA

Step-by-step explanation:

we know that

If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)

In this problem

LK=MJ

∠KLJ=∠KMJ

∠LKJ=∠MJK

so

Two angles and the included side is equal in triangle JKL and triangle KJM

therefore

JKL≅KJM ----> by ASA

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Answer:

12x+4y=40

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12 12

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3 years ago
What is the minimum number of points through which a line is drawn
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4 years ago
Please help. Will give brainliest.
evablogger [386]
Alright, so you have the basic formula- good.
You have the A value (400), the interest rate r (7.5% -> .075 in decimal), and the final P value (8500). So, we only need to solve for t.

8500 = (400)(1+.075)^t
/400      /400
21.25 = 1.075^t
logarithms are the inverse of exponents, basically, if you have an example like
y = b^x, then a logarithm inverts it, logy(baseb)=x
Makes sense if you consider a power of ten.
1000 = 10^3
if you put logbase10(1000), you'll get 3.
Anyways, though, to solve the problem make a log with a base of 1.075 in your calculator
log21.25(base 1.075) = t
also, because of rules of change of base (might want to look this up to clarify), you can write this as log(21.25)/log(1.075) = t
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6 0
3 years ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

152=190-Ae^{-14k}.e^{14k}

Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

0.5=e^{-14k}

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76

Dividing by 0.5

A=152

7 0
3 years ago
Your bedroom ceiling if 10 feet high and is two-thirds as high as the living room ceiling. Write and solve an equation to find t
timurjin [86]
Ht of ceiling = 10 ft which is two-thirds of living rm ceiling
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3 years ago
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