Is ∆JKL ≅ ∆KJM ? Justify your answer below.
2 answers:
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So for this triangle you are going to use Cos, which is adjacent/hypotenuse.
In this case x is your hypotenuse.
So your equation is going to be Cos(49)= 14/x.
So in order to get x, you are going to have to multiply x by each side. So:
x • Cos(49)= 14/x • x.
Multiplying x and x is going to cancel each other out so your new equation is going to be:
xCos(49)=14.
Now we are going to divide each side by Cos(49). Dividing Cos(49) by itself, will cancel itself out, so then your new equation will be:
x = 14/Cos(49)
Now you are going to put that into your calculator and your answer will be
x = 9.18.
If i’m wrong please tell me and correct me.
Here is a photo of you don’t understand.
In this case x is your hypotenuse.
So your equation is going to be Cos(49)= 14/x.
So in order to get x, you are going to have to multiply x by each side. So:
x • Cos(49)= 14/x • x.
Multiplying x and x is going to cancel each other out so your new equation is going to be:
xCos(49)=14.
Now we are going to divide each side by Cos(49). Dividing Cos(49) by itself, will cancel itself out, so then your new equation will be:
x = 14/Cos(49)
Now you are going to put that into your calculator and your answer will be
x = 9.18.
If i’m wrong please tell me and correct me.
Here is a photo of you don’t understand.