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Firdavs [7]
3 years ago
10

Seven less than the quotient of x and 9

Mathematics
1 answer:
bulgar [2K]3 years ago
8 0
X/9 - 7 is the answer. note x/9 is in fraction form
 

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Write an equation for the translation of y=|x|. 2 units down.
Bezzdna [24]
B. Y = <span>|x| - 2
when moving left or right...meaning moving horizontally.......the number is added inside the parenthesis. 

This one is moving up or down ....meaning moving horizontally........so the number is added outside the parenthesis. If it moves up then add(+)..........if it moves down then subtract(-). The formula used for horizontal shifts is, y=lXl + k
.Here k will become negative or remain positive based on the given data.

Now,
It's a horizontal shift, so we can eliminate C and D.
 It moves down so we will subtract and therefore we can eliminate A

so the answer is B.
 lets check our answer by using the formula

Y = lxl + k
moves 2 units down so our k = (-2)
Y = lxl + (-2)  [substitute k]
Y = lxl - 2

</span>
6 0
3 years ago
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What is the slope of the line represented by the equation 2x+3y= –12 ? –32 –23 23 32
mr_godi [17]

Answer:

Option 2 - m=-\frac{2}{3} is the slope of the equation.

Step-by-step explanation:

Given : Equation 2x+3y=-12

To find : What is the slope of the line represented by the equation ?

Solution :

The slope form of line is y=mx+c

Equation 2x+3y=-12

Take 2x to another side,

3y=-12-2x

Divide 3 both side,

y=\frac{-12-2x}{3}

y=\frac{-2}{3}x-4

On comparing with general equation,

m=-\frac{2}{3} is the slope of the equation.

Therefore, option 2 is correct.

7 0
3 years ago
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FREE PONITS<br><br><br><br> oof its really late for me lol
irinina [24]
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7 0
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Which of the following are undefined terms?<br> A. Point<br> B. Segment<br> C. Plane<br> D. Angle
Damm [24]
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3 0
4 years ago
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Use the given degree of confidence and sample data to construct a confidence interval for the population mean mu.Assume that the
worty [1.4K]

Answer:

<em>95% confidence interval for the true mean cholesterol content of all such eggs.</em>

<em>(173.8175 , 196.1825)</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the sample  x⁻ = 185 milligrams</em>

<em>Given standard deviation of the sample 'S' = 17.6 milligrams</em>

<em>Level of significance </em>

<em>                  ∝ = 0.05</em>

t_({\frac{\alpha }{2} , n-1 }) = t_{0.025 ,11} =  2.2010

<u><em>Step(ii)</em></u>:-

95% confidence interval for the true mean cholesterol content of all such eggs.

(x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} })

(185 - 2.2010 \frac{17.6}{\sqrt{12} } , 185 + 2.2010 \frac{17.6}{\sqrt{12} })

( 185 - 11.1825 , 185 + 11.1825)

(173.8175 , 196.1825)

<u><em>Final answer:-</em></u>

<em>95% confidence interval for the true mean cholesterol content of all such eggs.</em>

<em>(173.8175 , 196.1825)</em>

<u><em></em></u>

3 0
3 years ago
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