4 > 6*t
Number t refers to an unknown. In this case, t can only be 0, because 6*0 = 0, and 4 > 0 or four is greater than 0.
Answer:
.
Step-by-step explanation:
Since repetition isn't allowed, there would be
choices for the first donut,
choices for the second donut, and
choices for the third donut. If the order in which donuts are placed in the bag matters, there would be
unique ways to choose a bag of these donuts.
In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type
times.
For example, if a bag includes donut of type
,
, and
, the count
would include the following
arrangements:
Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count
by
to find the actual number of donut combinations:
.
Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of
objects from a set of
distinct objects:
.
9.75 i think I’m not really sure do you have any options?
Answer:
$-19.35 or -19.35 aprox
Step-by-step explanation:
1. Observe that the f(t) is change by 4 per time t => there's a acceleration of 4 => f''(t) = 4; Take the derivative of it we can get a velocity function. f'(t) = 4t + c. Since the velocity from 100 to 80 is -20 (average), this means at t = 0, f'(0) = -22 => f'(t) = 4t - 22; Take the derivative again to get the position function: f(t) = 2t^2 - 22t + d, here d = 100 should be trivial. So, the function that models the relationship is f(t) = 2t^2 - 22t + 100.
2. By the compound interest formula:
A = P (1 + r/n)^(nt) , since it's yearly, so n = 1;
results A(t) = 100 (1+0.12)^t.
3. The average rate of change is basically finding the slope, m = y1 - y2 / x1 - x2.