Answer:
4.2 kanban containers required
Step-by-step explanation:
Given the following information :
Waiting time = 0.25 days
Average peocessing time = 0.15 days / container
Daily usage (Demand rate) = 2000 per day
Container capacity = 200 wheels
Policy variable ( Alpha) = 5% = 0.05
Therefore, number of kanban containers needed for the wheels can be calculated using:
(Number of containers(x) * container size) = (Demand rate (waiting time + processing time)*(1 + alpha))
x * 200 = 2000(0.25 + 0.15)*(1 + 0.05)
200x = 2000(0.40)*(1.05)
200x = 840
x = 840 / 200
x = 4.2
4.2 kanban containers required
Answer:
FV= 9,716
Step-by-step explanation:
Giving the following information:
Present value (PV)= 12,400
Decrease rate (d)= 5%
Number of periods (n)= 5 years
<u>To calculate the enrolment value (future value) after 5 years, we need to use the following formula:</u>
FV= PV / (1 + d)^n
FV= 12,400 / (1.05^5)
FV= 9,716
Since the bases are the same you can subtract the exponents. All you have to do is 5-2, which is 3 therefore the answer is x^3.
A(1) = 6 = d + c
<span>a(4) = 33 = 4d + c </span>
<span>3d = 27=> d=9 </span>
<span>c = -3 </span>
<span>a(2) = 9(2) - 3 = 15 </span>
<span>a(3) = 15 + 9 = 24</span>
Answer:
see step-by-step below
Step-by-step explanation:
1) y - 2 > 3
Add 2 to both sides: y > 5
2) y ≤ 2
Draw a closed circle at y = 2 then shade the numbers to the left
3) y ≥ 250
where y = savings
4) The image isn't very clear, so I can't tell if it's a closed or open circle on -4.
If it is closed, it will be y ≤ -4
If it is open, it will be y < -4
5) -4 < f
Draw an open circle at f = -4 then shade the numbers to the right
6) x < -3.5
Draw an open circle at x = -3.5 then shade the numbers to the left
7) closed circle ... shade to the left of 8 ... make y equal to or less than 8.
8) F ≤ 6
C - closed circle at 6 with shaded numbers to the left
9) y > 2.75
Betty saved more than $2.75 every month
10) 1 + x < 5
Subtract 1 from both sides: x < 4
11) x ≥ -2.5
12) 1 ≤ m means that m is equal to or greater than 1
solutions: 4, 1, 2.3