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3 years ago

14

Can someone help me on 6 or 7 (40 points)

2 answers:

adelina 88 [10]3 years ago

7 0

So I think that number 6 is just dividing by 3 and the second one doesn't like divide so number 7 is no and number 6 is yes

Mama L [17]3 years ago

6 0

I'm basically seeing if I take one of the numbers out then cross multiply, and see if I get the same number I took out or not.
6. I'm taking the 2 out for this one.
6*8=48
48/ 24=2
it should be proportional.

7.I'm taking out the 2
5*8= 40
40/25= 1.6
this one should not be proportional

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2 years ago

For what value of x would the expression below be undefined? 6x − 9 x − 5

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6 - 9 = - 3

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3 0

3 years ago

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago