<h3>Explanation:</h3>
GCF: the greatest common factor of numerator and denominator is a factor that can be removed to reduce the fraction.
<em>Example</em>
The numerator and denominator of 6/8 have GCF of 2:
6/8 = (2·3)/(2·4)
The fraction can be reduced by canceling those factors.
(2·3)/(2·4) = (2/2)·(3/4) = 1·(3/4) = 3/4
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LCM: the least common multiple of the denominators is suitable as a common denominator. Addition and subtraction are easily performed on the numerators when the denominator is common.
<em>Example</em>
The fractions 2/3 and 1/5 can be added using a common denominator of LCM(3, 5) = 15.
2/3 + 1/5 = 10/15 + 3/15 = (10+3)/15 = 13/15
Answer:
Step-by-step explanation: First, you need to write all your data down from least to greatest. Next, count up all the numbers to see how many students. Then you want to find the mean which is average (add then divide). Median is the middle so you will x each number out till you get to the middle, and if the middle is 2 numbers, you find the average of them to find the median. Mode means most often. Range is highest minus lowest. And you can do the next 2.
Yes it is correct because you would multiply 30 by 7 which equals 210 + the extra 20 dollars / 50 dollars (idk).. she will have more than enough though
Marked(10)/total = 3/20 (from sample)
total/10 = 20/3 (inverting the above proportion)
total = 10•20/3 = 200/3 ≈ 67
What does the central limit theorem tell us about the
distribution of those mean ages?
<span>A. </span>Because n>30, the sampling
dist of the mean ages can be approximated by a normal dist with a mean u and a
SD o/sqrt 54,
Whenever n<span>>30 the central limit theory applies.</span>
