34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.



Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. 
Here μ to μ + σ = 
Hence 34% of the scores lie between 433 and 523.
Im not that good with these types of problems but i think it is b if my math is correct.
Answer: The answer would be j=19
Answer:
50
Step-by-step explanation:
since the Pythagorean theorem is
√
b is the bottom line (48)
a is the right line (14)
c is the top line (c)
plug that in
√
then do the exponets
= 14 * 14 = 196
= 48 * 48 = 2304
then add them together
196 + 2304 = 2500
√2500
the sqrt of 2500 is 50 (50 * 50 = 2500)
c = 50
your answer is 50
hope this helps:)
Answer:
I don't need to prove it, I already believe you