Question

Power (denoted by PPP) can be defined as a function of work (denoted by WWW) and time (denoted by ttt) using this formula: P=\dfrac{W}{t}P= t W ​ P, equals, start fraction, W, divided by, t, end fraction Work is measured in \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2} s 2 kg⋅m 2 ​ start fraction, start text, k, g, end text, dot, start text, m, end text, squared, divided by, start text, s, end text, squared, end fraction, and time is measured in \text{s}sstart text, s, end text. Select an appropriate measurement unit for power. Choose 1 answer:

Answer 1

Answer:

$\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

Step-by-step explanation:

Power (denoted by P) can be defined as a function of work (denoted by W) and time (denoted by t) using this formula:

$P=\dfrac{W}{t}$

Unit of Work = $\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2}$

Unit for Time = s

Therefore, the Unit of Power

$= Unit for W \times \dfrac{1}{\text{Unit for time}}$

$=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2} \times \dfrac{1}{s} \\=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

An appropriate unit for power is: $\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$