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kobusy [5.1K]
2 years ago
6

Please help me I don't get it 7 1/5−(−3/5)

Mathematics
1 answer:
Fudgin [204]2 years ago
8 0

Answer:

39/5

Step-by-step explanation:

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At sally's diner, combo meals come with either chips or fries. of the 115 customers on Friday 80% ordered combo means. of these
34kurt

3/4 = 0.8

115 x 0.8 = 92

Final Answer:

D. 92

4 0
2 years ago
Need help with what the answer to this question is
levacccp [35]
The answer is C
C has units of Markers / Markers on the left and Money over an unknown which represents money.

None of the others (D) is incorrect, because we've already chosen C.

A is not because.you have the wrong amount of money divided by the larger number of makers. 

B does not work because the right is markers divided by money. The left had side will have money divided by markers. It won't work. The safest way to  these questions up is to keep the knows on the left and put the unknown on the left with the number it is associated with.
Let's see why the others don't work.

5 0
3 years ago
120 times 1/2<br>Do not divide, whole number times fraction.​
andreyandreev [35.5K]

Answer:

60

Step-by-step explanation:

write 120 like this: 120/2

Then just multiply the numerators.

Which gets you 120/2.

Then change it it to a mixed fraction which is 60.

7 0
2 years ago
Does the statement "3x8 = 4x6" illustrate the communtative property of multipulcation
Alenkasestr [34]
Yes "3x8 = 4x6" does illustrate the commutative property of multiplication.
7 0
2 years ago
Read 2 more answers
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
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