Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.
x+2y=6
x-y=3
Multiply the bottom equation by two so then you have:
x+2y=6
2x-2y=6
The y's now cancel out:
x=6
2x=6
Add them together
3x=12
Divide
x=4.
To find y, plug x into either equation (*don't have to do both, but I will)
(4)+2y=6
(4)-y=3
Subtract four
2y=2
-y=-1
Divide each
2y/2 = 2/2
y=1
-y/-1 = -1/-1
y=1
The answer is:
x=4
y=1
I hope that helps!
Answer: i dont get what u mean explain
Step-by-step explanation:
Answer:
3>=3
Step-by-step explanation:
2(4+2x)>=5x+5
distribute the 2: 8+4x>=5x+5
8>=x+5
3>=x
Answer:
(-√(6-√26) < x < √(6-√26)) ∪ (x < -√(6 +√26)) ∪ (√(6 +√26) < x)
Step-by-step explanation:
Using x^2 = z, the equation can be rewritten as ...
z^2 -12z +10 > 0
(z -6)^2 -26 > 0
|z -6| > √26
This resolves to two equations.
This one ...
x^2 -6 < -√26 . . . . substitute x^2 for z
|x| < √(6-√26) . . . . add 6, take the square root; use √a^2 = |a|
-√(6-√26) < x < √(6-√26)
__
and this one ...
x^2 -6 > √26
|x| > √(6 +√26)
x < -√(6 +√26) ∪ √(6 +√26) < x
Answer:
y I z
Step-by-step explanation:
We can see that y I b and z I b we can conclude also that
y I z.
