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Leviafan [203]
3 years ago
6

I had 3 apples. I add 2 more apples. How many apples do I have?

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

5 lol

Step-by-step explanation:

You might be interested in
Prove that for any natural n the number 3^(n+4)−3^n is divisible by 16.
gtnhenbr [62]

Answer:

Proved (See Explanation)

Step-by-step explanation:

Show that 3ⁿ⁺⁴ - 3ⁿ is divisible by 16.

This is done as follows

\frac{3^{n+4} - 3^n}{16}

From laws of indices;

aᵐ⁺ⁿ = aᵐ * aⁿ.

So, 3ⁿ⁺⁴ can be written as 3ⁿ * 3⁴.

\frac{3^{n+4} - 3^n}{16} becomes

\frac{3^n * 3^4 - 3^n}{16}

Factorize

\frac{3^n(3^4 - 1)}{16}

\frac{3^n(81 - 1)}{16}

\frac{3^n(80)}{16}

3ⁿ * 5

5(3ⁿ)

<em>The expression can not be further simplified.</em>

<em>However, we can conclude that when 3ⁿ⁺⁴ - 3ⁿ is divisible by 16, because 5(3ⁿ) is a natural whole number as long as n is a natural whole number.</em>

3 0
3 years ago
In a right triangle, the hypotenuse has endpoints XY, shown on the graph. On a coordinate plane, line X Y has points (negative 4
Naya [18.7K]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is A, B, and C?
marta [7]

Answer:

A = 46

B = 134

C = 78

Step-by-step explanation:

5 0
3 years ago
Don't mind this.......
DIA [1.3K]

Answer:

okay thank you for free points

4 0
3 years ago
Read 2 more answers
A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.​
gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅ is double a₇ , then

a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

- 8d = a₁

The sum of n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , substitute values

S_{17} = \frac{17}{2} ( 2(- 8d) + 16d)

     = 8.5(- 16d + 16d)

     = 8.5 × 0

     = 0

5 0
2 years ago
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