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3 years ago

14

How many moles are there in 1.2 x 10^2 atoms of sulfur

1 answer:

Mariulka [41]3 years ago

5 0

Avogadro's number tells you that in one mol of element (sulfur) there are 6.022x10^23 atoms...

So,

1 mol : 6.022x10^23 = x mol : 1.2x10^2

x = 1.99 x 10^-22 mol

*Although this should be correct, you might want to check your question again. You probably misinterpret the question... you want 1.2x10^23 !! :) check it.

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The energy transfer between the system and the surroundings, in the form of heat at constant pressure is described by which of t

kicyunya [14]

I think the answer would be d but not 100% sure

4 0

3 years ago

The chemical formula of bromomethane is BrCH3. Which correctly describes the number of atoms of each element in bromomethane?

Anit [1.1K]

The number of atoms of each element :

C : 1 atom

H : 3 atoms

Br = 1 atom

<h3>Further explanation</h3>

Given

Bromomethane-CH₃Br

Required

The number of atoms

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

The number of atoms in a compound is generally indicated as a subscript after the atom

C : 1 atom

H : 3 atoms

Br = 1 atom

Total 5 atoms

4 0

2 years ago

If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a

strojnjashka [21]

Answer : The final temperature of the mixture is, $22.14^oC$

Explanation :

First we have to calculate the mass of ethanol and water.

$\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g$

and,

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g$

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.42J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol = 35.5 g

$m_2$ = mass of water = 45.0 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $8.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get:

$35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.14^oC$

Therefore, the final temperature of the mixture is, $22.14^oC$

3 0

3 years ago

1/2 - 3/7=??????????????????????

Veseljchak [2.6K]

1/2 - 3/7 = 7/14 - 6/14 = 1/14

6 0

2 years ago

40 Points Need help ASAP

Sveta_85 [38]

It requires a force in the direction opposite to the motion of the object for it to slow down.

3 0

2 years ago