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pshichka [43]
3 years ago
9

A vessel of 356 cm3 capacity contains oxygen at a pressure of 760 mmHg and temperature of 15 oC. Assuming that the volume remain

s constant, calculate: (10 points)
(a) the pressure inside the vessel when it was warmed to 100 oC

(b). the temperature to which it must be raised to give a pressure of 2 atm.​
Chemistry
1 answer:
liq [111]3 years ago
8 0


(a) the pressure inside the vessel when it was warmed to 100 oC

(
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Calculate the number of moles in the following: 2.8 X 10^24 atoms of Cl2
vova2212 [387]

Answer:

<h3>The answer is 4.65 moles</h3>

Explanation:

To find the number of moles given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.8 × 10²⁴ atoms of Cl2

So we have

n =  \frac{2.8 \times  {10}^{24} }{6.02 \times  {10}^{23}  }  \\  = 4.65116279069...

We have the final answer as

<h3>4.65 moles</h3>

Hope this helps you

7 0
3 years ago
Choose the element that IS NOT in the same period as Potassium.
Lesechka [4]
E. sodium is the answer

8 0
3 years ago
Which change is most likely to occur when a molecule of H2 and a molecule of I2 collide with proper orientation and sufficient e
bazaltina [42]
The collision of the molecules between the hydrogen molecule or H2, and an iodine molecule or I2, provided there would be a sufficient energy is that the system would eventually undergo a chemical change wherein a new chemical compound would be formed from these two molecules.
8 0
3 years ago
Read 2 more answers
A child has a toy balloon with a volume of 1.80 L. The temperature of the balloon when it was filled was 293 K at a pressure of
Mekhanik [1.2K]

Answer:

2.42L

Explanation:

Given parameters:

V₁  = 1.8L

T₁ = 293K

P₁  = 101.3kPa

P₂ = 67.6kPa

T₂  = 263K

Unknown:

V₂ = ?

Solution:

To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;

               \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

All the units are in the appropriate form. We just substitute and solve for the unknown;

         101.3 x 1.8 / 293    =     67.6 x V₂  /  263

          V₂   = 2.42L

7 0
3 years ago
When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

7 0
3 years ago
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