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Serggg [28]
2 years ago
9

Draw the structure of the major organic product(s) for the following reaction between an acetylenic anion and an alkyl halide. (

The reaction stoichiometry is 1:1.) A carbon carbon triple bond where carbon 1 is a carbanion with a lone pair and carbon 2 is bonded to methyl. This reacts with a 5 carbon chain where carbon 3 has a bromine substituent.
Chemistry
1 answer:
MaRussiya [10]2 years ago
8 0

Answer:

See explanation below

Explanation:

In this case, we are having a reaction between an anion and alkyl halide. The carbon 1 of the anion will act as nucleophile and will attack the electrophile, which is 5 carbon chain with the bromine in the third carbon.

Now, the nucleophyle is an alkyne of 3 carbon. According to the description, it should be:

CH₃ - C ≡ C⁻

And the alkyl halide is:

CH₃ - CH₂ CH(Br) - CH₂ - CH₃

And the final product after the reaction would be the following:

CH₃ - C ≡ C - CH - (CH₂CH₃)₂

However, in the attached picture you can see this better and the mechanism of reaction.

Hope this helps

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6 0
2 years ago
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5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------&gt; 1 Mg3(
professor190 [17]

Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

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3 years ago
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Rainbow [258]
True would be the answer
7 0
2 years ago
How do you convert from grabs to moles of a substance
Lorico [155]

The correct question is as follows:

How do you convert from grams to moles of a substance

1. Divide by the molar mass

2. Subtract the molar mass

3. Add the molar mass

4. Multiple by the molar mass

Answer: In order to convert from grams to moles of a substance divide by the molar mass.

Explanation:

The number of moles of a substance is the mass of substance in grams divided by its molar mass.

The formula to calculate moles is as follows.

Moles = \frac{mass}{molar mass}

This means that grams are converted to moles when grams is divided by molar mass.

Thus, we can conclude that in order to convert from grams to moles of a substance divide by the molar mass.

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