Draw the structure of the major organic product(s) for the following reaction between an acetylenic anion and an alkyl halide. (
1 answer:
Answer:
See explanation below
Explanation:
In this case, we are having a reaction between an anion and alkyl halide. The carbon 1 of the anion will act as nucleophile and will attack the electrophile, which is 5 carbon chain with the bromine in the third carbon.
Now, the nucleophyle is an alkyne of 3 carbon. According to the description, it should be:
CH₃ - C ≡ C⁻
And the alkyl halide is:
CH₃ - CH₂ CH(Br) - CH₂ - CH₃
And the final product after the reaction would be the following:
CH₃ - C ≡ C - CH - (CH₂CH₃)₂
However, in the attached picture you can see this better and the mechanism of reaction.
Hope this helps
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Answer: Option (B) is the correct answer.
Explanation:
Both oxygen and fluorine are period 2 elements and when we move across a period then there occurs a decrease in atomic size of the atoms. Hence, the atomic radius of a neutral fluorine atom is smaller than a neutral oxygen atom.
Moreover, atomic number of fluorine is 9 and it has higher nuclear charge due to which it will cause more attraction of electrons. As a result, size of a fluorine ion will be smaller.
On the other hand, size of oxygen atom is larger and has small nuclear charge due to which attraction of electrons by its nucleus will not be strong enough. Hence, the size of will be larger.
Thus, we can conclude that the statement has a larger nuclear charge than
has, is correct for the fact that the
ion is smaller than the
ion.