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valina [46]
3 years ago
12

Adrian has a square bedroom. The area of the room is 169 ft². How would you find the length of one side of his room?

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0
To find the length of one sides of the square, you must find the square root of the area. Therefore, your answer would be 13.
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1. Write out the law of cosines and find the hypotenuse of triangle with 2 sides lengths equal to three and the included angle m
LUCKY_DIMON [66]

Answer:

1.) \sqrt{13.341}  ≈ 3.652

2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.

Step-by-step explanation:

I think we may have the same class so hopefully this helps:

1.) a^2 = b^2 + c^2 - 2bccosA --> law of cosines formula.

   a^2 = 3^2 + 3^2 - 2(3)(3)cos(75) --> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.

   a^2 = 18 - 18cos75 --> in between steps.

   a^2 = 13.341 --> more simplifying.

   a(hypotenuse) = \sqrt{13.341} or 3.652 --> answer

2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.

Good luck! :)

   

6 0
3 years ago
Please help me! Thanks
Yuki888 [10]

Answer:

The answer is D. 22

Step-by-step explanation:


4 0
3 years ago
Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
enyata [817]

Answer:

Step-by-step explanation:

It is true that for any given odd integer, square of that integer will also be odd.

i.e if m is and odd integer then m^{2} is also odd.

In the given proof the expansion for (2k + 1)^{2} is incorrect.

By definition we know,

(a+b)^{2} = a^{2} + b^{2} + 2ab

∴ (2k + 1)^{2} = (2k)^{2} + 1^{2} + 2(2k)(1)\\(2k + 1)^{2} = 4k^{2} + 1 + 4k

Now, we know 4k^{2} and 4k will be even values

∴4k^{2} + 1 + 4k will be odd

hence (2k + 1)^{2} will be odd, which means m^{2} will be odd.

7 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!​
Darya [45]

Answer:

Valid

Step-by-step explanation:

No calculations, but,

Def. of isosceles triangle= two congruent sides.

7 0
4 years ago
Read 2 more answers
Your math teacher given you 20 questions . 15 % Of the assignment is done. How many is completed
Semenov [28]

Answer:

3

Step-by-step explanation:

20×0.15

equal 3

3 0
3 years ago
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