An acrobat was launched toward a water tank, with an upward velocity of 48 feet per second. The launch point was 32 feet below t

Question

4 years ago

7

An acrobat was launched toward a water tank, with an upward velocity of 48 feet per second. The launch point was 32 feet below t

he water level in the tank. Use the quadratic equation 0 = -16t2 + 48t – 32 to find how much time, t, it took for her to reach the water level in the tank.

Mathematics

1 answer:

ludmilkaskok [199] · Answer 1 · 2021-12-21T21:33:31+03:00

ludmilkaskok [199]4 years ago

3 0

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