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vichka [17]
3 years ago
12

How is the climate near the equator different from the climate near the poles? What causes this difference.

Chemistry
2 answers:
Igoryamba3 years ago
4 0
<span>The climate near the equator is hot and dry, think of the Sahara desert.  The climate near the north and south poles is very cold for almost the whole year.</span>
LUCKY_DIMON [66]3 years ago
3 0
The climate near the equator is hot and dry, think of the Sahara desert.  The climate near the north and south poles is very cold for almost the whole year.

One of the reasons for this is that as the earth orbits the sun the sun's rays are most intense for regions near the equator.  Depending on the time of year, the sun's rays can be very weak near the poles, and if you are close enough to the poles there are days in deep winter when the sun does not even rise over the horizon!
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What is the volume of 1.2 moles of oxygen gas (O2) at standard temperature and pressure (STP)?
REY [17]
Volume of O2 = 22.4 x moles of O2
                       =  22.4 x 1.2
                       =      26.88L
5 0
3 years ago
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Silver chloride breaks down to form silver and chlorine in the presence of light. what type of reaction is this? A combination r
Veronika [31]
A decomposition reaction<span> is a type of chemical </span>reaction<span> in which a single compound breaks down into two or more elements or new compounds. These </span>reactions<span> often involve an energy source such as heat, light, or electricity that breaks apart the bonds of compounds. so it is a decomposition reaction because the silver chloride breaks down into silver and chlorine</span>
3 0
4 years ago
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What is the mass of a sample containing 8.53×10 to the 24th power formula units of magnesium phosphate?
Archy [21]

Answer:

Mass = 3732.62 g

Explanation:

Given data:

Number of formula units = 8.53×10²⁴

Mass of sample = ?

Solution:

1 mole of any substance contain 6.022×10²³ formula units.

8.53×10²⁴ formula units ×1 mol / 6.022×10²³ formula units

1.42×10¹ mol

14.2 mol

Mass of magnesium phosphate:

Mass = number of moles × molar mass

Mass = 14.2 mol × 262.86 g/mol

Mass = 3732.62 g

5 0
4 years ago
At what pressure would 11.1 moles of a gas occupy 44.8 L at 300 K?
faltersainse [42]

Answer:

P=6.10atm

Explanation:

Hello,

In this case, we can study the ideal gas equation that relates temperature, volume, pressure and moles as shown below:

PV=nRT

Thus, since we are asked to compute the pressure y simply solve for it as follows:

P=\frac{nRT}{V}=\frac{11.1mol*0.082\frac{atm*L}{mol*K}*300K}{44.8L}\\  \\P=6.10atm

Best regards.

5 0
3 years ago
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

5 0
3 years ago
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