Answer:
10.1g of H₂ are produced
Explanation:
To solve this question we need, first, to convert the mass of each reactant to moles and, using the chemical reaction, find limiting reactant. With limiting reactant we can find the moles of H2 and its mass:
<em>Moles Zn -Molar mass: 65.38g/mol-:</em>
307g * (1mol / 65.38g) = 4.696 moles
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
381g HCl * (1mol / 36.46g) = 10.45 moles
For a complete reaction of 10.45 moles of HCl are required:
10.45 moles HCl * (1mol Zn / 2mol HCl) = 5.22 moles Zn
As there are 4.696 moles of Zn, <em>Zn is the limiting reactant</em>
<em />
The moles of H₂ produced = Moles of Zn added = 4.696 moles. The mass is-Molar mass H₂ = 2.16g/mol-:
4.696 moles * (2.16g / mol) =
<h3>10.1g of H₂ are produced</h3>
Are found along volcanic island arcs
<u>Given:</u>
Concentration of Cr2+ = 0.892 M
Concentration of Fe2+ = 0.0150 M
<u>To determine:</u>
The cell potential, Ecell
<u>Explanation:</u>
The half cell reactions for the given cell are:
Anode: Oxidation
Cr(s) ↔ Cr2+(aq) + 2e⁻ E⁰ = -0.91 V
Cathode: Reduction
Fe2+ (aq) + 2e⁻ ↔ Fe (s) E⁰ = -0.44 V
------------------------------------------
Net reaction: Cr(s) + Fe2+(aq) ↔ Cr2+(aq) + Fe(s)
E°cell = E°cathode - E°anode = -0.44 - (-0.91) = 0.47 V
The cell potential can be deduced from the Nernst equation as follows:
Ecell = E°cell - (0.0591/n)log[Cr2+]/[Fe2+]
Here, n = number of electrons = 2
Ecell = 0.47 - 0.0591/2 * log[0.892]/[0.0150] = 0.418 V
Ans: The cell potential is 0.418 V
Covalent bond forms between the oxygen and hydrogen atoms.
(I attached a picture that could help)
-Hope that helps,
Good luck!
Answer:
441.28 g Oxygen
Explanation:
- The combustion of hydrogen gives water as the product.
- The equation for the reaction is;
2H₂(g) + O₂(g) → 2H₂O(l)
Mass of hydrogen = 55.6 g
Number of moles of hydrogen
Moles = Mass/Molar mass
= 55.6 g ÷ 2.016 g/mol
= 27.8 moles
The mole ratio of Hydrogen to Oxygen is 2:1
Therefore;
Number of moles of oxygen = 27.5794 moles ÷ 2
= 13.790 moles
Mass of oxygen gas will therefore be;
Mass = Number of moles × Molar mass
Molar mass of oxygen gas is 32 g/mol
Mass = 13.790 moles × 32 g/mol
<h3> = 441.28 g</h3><h3>Alternatively:</h3>
Mass of hydrogen + mass of oxygen = Mass of water
Therefore;
Mass of oxygen = Mass of water - mass of hydrogen
= 497 g - 55.6 g
<h3> = 441.4 g </h3>
