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astra-53 [7]
3 years ago
12

How many protons electrons and neutrons respectively does 29 CS have

Chemistry
1 answer:
irakobra [83]3 years ago
8 0

55 \; \text{e}^{-}, 55 \; \text{p}^{+}, and 74 \; \text{n}^{0}- in case cesium-129 is what you were referring to.

Cesium has atomic number 55 as seen on a modern periodic table. A cesium atom nucleus would thus contain an equal number of protons; in addition to that, a <em>neutral</em> atom of cesium would contain the same number of electrons in its electron cloud.

For a particular isotope,

\text{Mass number} = \text{Number of protons per nuclei} + \text{Number of Neutrons per nuclei}.

This isotope of cesium has a mass number of 129 and contains 55 protons in each atomic nucleus. One cesium nuclei would therefore contain 129 - 55 = 74 neutrons.

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What is the molar mass of magnesium tartrate
Leya [2.2K]

Answer:

172.385 g/mol

Explanation:

Magnesium Tartrate is C4H4MgO6

C - 12.01 g/mol

H - 1.01 g/mol

Mg - 24.305 g/mol

O - 16.00 g/mol

12.01(4) + 1.01(4) + 24.305 + 16(6) = 172.385 g/mol

3 0
4 years ago
Read 2 more answers
Balance the chemical equation
brilliants [131]

Answer:

Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2

Explanation:

Fe_2O_3+CO\Rightarrow \:2Fe+CO_2\\\\Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2

Best Regards!

8 0
3 years ago
In a particular experiment at 300 ∘C, [NO2] drops from 0.0100 to 0.00800 M in 100 s. The rate of appearance of O2 for this perio
Tems11 [23]

Answer:

1\times{10}^{-5}\frac{M}{s}

Explanation:

The stoichiometry for this reaction is  

2NO_2\rightarrow2NO+O_2

The rate for this reaction can be written as  

-r_{NO_2}=-\frac{d\left[NO_2\right]}{dt}=\frac{(0.01-0.008)M}{100s}=2\times{10}^{-5}\frac{M}{s}

This rate of disappearence of NO_2 can be realated to the rate of appearence of O_2 as follows  (the coefficients of each compound are defined by the stoichiometry of the reaction)

-r_{O_2}=-r_{NO_2}\times\frac{coefficient\ O_2\ }{coefficient\ NO_2}=2\times{10}^{-5}\frac{M}{s}\times\frac{1\ mole\ O_2\ }{2\ mole\ NO_2}=1\times{10}^{-5}\frac{M}{s}

6 0
4 years ago
A board of wood has a density of 0.487 g/cm3. The board is measured to have a length of 3.21 cm, a width of 12.2 cm and a height
ivolga24 [154]

Answer:

The mass of board is 1.52 g.

Explanation:

Given data:

Density of wood = 0.487 g/cm³

Length of board = 3.21 cm

Width of board = 12.2 cm

Height of board = 0.80 mm (0.80/10=0.08 cm)

Mass of board = ?

Solution:

We know that density of an object is equal to the mass of substance divided by its volume. So we can calculate the mass from density formula.

Formula:

D = m/v

d = density

m = mass

v = volume

Now we will calculate the volume first.

V = length × width × height

V = 3.21 cm × 12.2 cm × 0.08 cm

V = 3.13cm³

Now we will calculate the mass.

D = m/v

0.487 g/cm³ = m/ 3.13 cm³

m = 0.487 g/cm³ × 3.13 cm³

m = 1.52 g

The mass of board is 1.52 g.

5 0
3 years ago
Part 1: Draw the major organic product for the proton transfer reaction between sodium hydride and ethanol; be sure to include l
valina [46]

Answer:

Major product ethoxide ion

Explanation:

  • Sodium hydride acts as a strong base towards ethanol.
  • Hydride ion abstracts one proton from -OH group in ethanol to produce sodium ethoxide and hydrogen gas.
  • It is an example of acid-base reaction where sodium hydride acts as a base and ethanol acts as an acid
  • Structure of major organic product i.e. ethoxide ion has been shown below.

4 0
3 years ago
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