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astra-53 [7]
3 years ago
12

How many protons electrons and neutrons respectively does 29 CS have

Chemistry
1 answer:
irakobra [83]3 years ago
8 0

55 \; \text{e}^{-}, 55 \; \text{p}^{+}, and 74 \; \text{n}^{0}- in case cesium-129 is what you were referring to.

Cesium has atomic number 55 as seen on a modern periodic table. A cesium atom nucleus would thus contain an equal number of protons; in addition to that, a <em>neutral</em> atom of cesium would contain the same number of electrons in its electron cloud.

For a particular isotope,

\text{Mass number} = \text{Number of protons per nuclei} + \text{Number of Neutrons per nuclei}.

This isotope of cesium has a mass number of 129 and contains 55 protons in each atomic nucleus. One cesium nuclei would therefore contain 129 - 55 = 74 neutrons.

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Which of the following statements is/are correct?
7nadin3 [17]

Answer:

All are correct

Explanation:

1) The angular momentum quantum number, l, are the subshells within a shell (principle quantum number) it talks about the "form" of an orbital, the number itself tells you about the number of angular nodes (a plane without electronic density). It starts at l=0 where you don't see any nodes and it takes the form of an sphere, and we knowing it bu another name an s-orbital. It takes values up to n-1.

l=0 (sphere - s-orbital)

l=1 (p-orbital)

l=2 (d-orbital)

2) The magnetic quatum number, ml relates to the number of orbitals within a subshell then it is related with l, taking values form -l to l incluing 0.

For l=0 (s-orbital) ml=0

For l=1 (p-orbital) ml=1,0,-1

For l=2 (d-orbital) ml=2,1,0,-1,-2

3) In every shell we are restricted by the total number of nodes of any orbital. Then if we want a d-orbital with l=3 we need at least 3 plane nodes only achievable with n=3 at least.

8 0
3 years ago
N₂(g) + 3H₂(g) → 2NH3(g)
Anna71 [15]

Answer:

93.5 moles N₂

Explanation:

To find the moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.0821 atm*L/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.

P = 95.0 atm                  R = 0.0821 atm*L/mol*K

V = 224 L                       T = 2773 K

n = ?

PV = nRT

(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)

21280 = n(227.6633)

93.5 = n

8 0
2 years ago
If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample?<br><br> show work plz
harkovskaia [24]

(\frac{17.8mole}{1} )( \frac{66grams}{1mole} ) \:  \:  \:  \:  17.8 \times 66 = 1.17 \times  {10}^{3} grams
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3
4 0
3 years ago
How many grams are there in 10.0 moles of Al2O3?
irinina [24]

Explanation:

1 mole is equal to 1 moles Al2O3, or 101.961276 grams.

8 0
3 years ago
What is the law of reciprocal proportion​
irina [24]

If two different elements combine separately with a fixed mass of a third element, the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine with each other.

7 0
3 years ago
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