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astra-53 [7]
3 years ago
12

How many protons electrons and neutrons respectively does 29 CS have

Chemistry
1 answer:
irakobra [83]3 years ago
8 0

55 \; \text{e}^{-}, 55 \; \text{p}^{+}, and 74 \; \text{n}^{0}- in case cesium-129 is what you were referring to.

Cesium has atomic number 55 as seen on a modern periodic table. A cesium atom nucleus would thus contain an equal number of protons; in addition to that, a <em>neutral</em> atom of cesium would contain the same number of electrons in its electron cloud.

For a particular isotope,

\text{Mass number} = \text{Number of protons per nuclei} + \text{Number of Neutrons per nuclei}.

This isotope of cesium has a mass number of 129 and contains 55 protons in each atomic nucleus. One cesium nuclei would therefore contain 129 - 55 = 74 neutrons.

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A car manufacturer needs to assemble the maximum number of cars using the following equation: 1 body frame + 4 wheels + 2 headli
larisa [96]

The wheels will be completely used up and  it is the limiting reactant in this case.

<h3>What is a limiting reactant?</h3>

The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

  • 60 breaks will be used for 30 engines and 30 body frame
  • 80 wheels will be used for 20 engines and 20 body frame
  • 64 headlights will be used for 32 engines and 32 body frame

The wheels will be completely used up and  it is the limiting reactant in this case.

Learn more about limiting reactants here: brainly.com/question/14222359

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8 0
2 years ago
Determine the mass in grams of 4.69 x 1021 atoms of barium. (The
Virty [35]

Answer:

1.07 g Ba

Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa

Best regards!

5 0
3 years ago
Is oatmeal a compound​
Alika [10]

Answer:

no

Explanation:

its made of a living organisim which in this case is oats

6 0
3 years ago
Read 2 more answers
Will lead (Pb) react with HgSO4?
lora16 [44]

Answer:

B

Explanation:

The electrochemical series can be used to check if a particular element has a greater activity than the other. Firstly, on the electrochemical series, it can be seen that lead is at a higher position compared to mercury. All things being equal, it will show a higher activity than mercury and hence can knock it off its salt.

Although it is the Overall standard electrode potential that tells us if a reaction is feasible or not, we can use the activity series to quickly discern if the reaction is possible or not. The overall standard electrode potential of both is positive which makes the reaction to be feasible and hence lead can display mercury off its salt

7 0
3 years ago
Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a
horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound            Amount

     Ni                        12.7 g

   CO                        1.98 g

Ni(CO)_4                  0.597 g

Calculate the value of the equilibrium constant.

<u>Answer:</u> The value of equilibrium constant for the reaction is 2448.1

<u>Explanation:</u>

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of Ni(CO)_4 = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M

\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M

\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M

For the given chemical reaction:

Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)

The expression of equilibrium constant for the reaction:

K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0
3 years ago
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