We will conclude that:
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
<h3>
Comparing the domains and ranges.</h3>
Let's study the two functions.
The exponential function is given by:
f(x) = A*e^x
You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:
y > 0.
For the logarithmic function we have:
g(x) = A*ln(x).
As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

So the range of the logarithmic function is the set of all real numbers.
<h3>So what we can conclude?</h3>
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
If you want to learn more about domains and ranges, you can read:
brainly.com/question/10197594
Right answer is C
We can solve it with the formula
y=mx+b
b is the point where graphic starts
Table C shows us 0 by x, and -4 by y
So the graph starts at (0, -4 )
Answer:
The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.
Step-by-step explanation:
Given

We know the rational zeros theorem such as:
if
is a zero of the function
,
then
.
As the
is a polynomial of degree
, hence it can not have more than
real zeros.
Let us put certain values in the function,
,
,
,
,
,
,
,
, 
From the above calculation results, we determined that
zeros as
and
.
Hence, we can check that

Observe that,
,
increases rapidly, so there will be no zeros for
.
Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18 will be true.