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nikdorinn [45]
3 years ago
14

* What is the sum? Complete the equation. –5.3+(-4.1) =

Mathematics
2 answers:
Vesna [10]3 years ago
5 0
I belive the answer to this question is -9.4 sorry if I’m wrong !
Tom [10]3 years ago
3 0

Answer:

-9.4

Step-by-step explanation:

–5.3+(-4.1) =

The signs are alike, so we add and take the sign

5.3+4.1 = 9.4

The sign is negative so we take the negative sign

-9.4

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Expand the expression. Fill in the blanks<br><br> 3(n + 7)<br><br> n +( <br> )7
morpeh [17]
3n + 21 is the answer
4 0
2 years ago
A building has 63 apartments and 70 bathrooms. What is the ratio of apartments to bathrooms in the building?
valina [46]

Answer:

63:70

Step-by-step explanation:

8 0
3 years ago
Unit activity: exponential and logarithmic functions
nirvana33 [79]

We will conclude that:

  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

y > 0.

For the logarithmic function we have:

g(x) = A*ln(x).

As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>
  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

3 0
1 year ago
Which of the following tables matches the graph below?
navik [9.2K]

Right answer is C

We can solve it with the formula

y=mx+b

b is the point where graphic starts

Table C shows us 0 by x, and -4 by y

So the graph starts at (0, -4 )

3 0
2 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
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