A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
Now we multiply it to get the polynomial
polynomial function of least degree with integral coefficients that has the
given zeros
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Well, you have to be given an interval. That is not an interval.
You should be given something like
If you add those fractions up you'll just get a point on the number line.
Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3
You'll end up with a point on 2/3
<span>(4x - 3y) • (16x2 + 12xy + 9y2)</span>
Well before the descimal its 5,600 after decimal is 0.56
The x4 would have to be in the parentheses while the -3 would have to be on the outside because you are subracting 3 from 48
4 cases of 12 bottled waters is 48 total amount of bottled waters since Veronica drank 3 she has 45 bottled waters left
