Answer:
8.54400374532
Step-by-step explanation:
Answer:
0.25feet
Step-by-step explanation:
The equation is not well written. Let the equation of the height be modelled as;
h = -16d²+8d+4
The velocity of the ball is zero at its maximum height.
Velocity = change in displacement/time
v = dh/dd
Differentiate
v = -32d+8
Since dh/dd = v = 0
0 = -32d+8
Add 32d to both sides
0+32d = 8
32d = 8
Divide both sides by 32
32d/32 = 8/32
d = 1/4
d = 0.25feet
Hence the maximum height of the tennis ball is 0.25feet
Note that the modeled equation was assumed. You can apply the same calculation to any equation given
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Answer:
4cm
Step-by-step explanation:
Given data
L=(2x+3)
W=(x-1)
P=28cm
A= L*W
A= (2x+3)*(x-1)
open bracket
A= 2x^2-2x+3x-3
collect like terms
A= 2x^2+x-3
P= 2L+2W
P= 2*(2x+3)+2(x-1)
P= 4x+6+2x-2
collect like terms
P= 6x-4
but p= 28
28= 6x-4
28-4= 6x
24= 6x
x= 24/6
x= 4cm
Hence x= 4cm
