Answer:
3
Step-by-step explanation:
This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Answer:
Step-by-step explanation:
y + 2 = 7(x - 2)
y + 2 = 7x + 14
y = 7x + 12
