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hichkok12 [17]
4 years ago
8

Round 76 to the nearest tenth

Mathematics
2 answers:
Elden [556K]4 years ago
8 0
The next larger tenth is  76.1 .
The next smaller tenth is  75.9 .

Neither of those is any closer to 76 than 76 is.

76 is already rounded to the nearest tenth.
Ksju [112]4 years ago
7 0
70 is the nearest tenth
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there are 24 marbles in a bag: 2/16 of the marbles are red, 1/8 of the marbles are blue, 1/4 of the marbles are yellow, 1/3 of t
Roman55 [17]

Answer: 3 red marbles, 3 blue marbles, 6 yellow marbles, 8 black marbles, 4 silver marbles

Step-by-step explanation:

I know these are the correct number of marbles because I set up these numbers as fractions and solved for x.

For examples, 2/16 of the marbles are red. 2/16=x/24

You would do this because we are trying to find the number of marbles that are red out of the 24 marbles.

Next, we would do 24 divided by 16= 1.5 Then 1.5 times 2=3

You would follow this rule for each fraction of marbles in order to find the true number of marbles out of 24.

4 0
3 years ago
Help I'm desperate it's near midnight and assignment due tomorrow rip me
andrey2020 [161]
The first one is categorical data
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3 0
3 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
Hello people who are good at math pls help me. ​
kherson [118]

Answer:

Q1. 12+3×2=N

12+6=N

18=N

Ans: D

Q2. 5+7×2=5+14

=19

Ans: A

Q3. 4-(3-2)+1×(15÷3)=N

4-1+1×5=N

4-1+5=N

8=N

Ans: A

Q4. 48÷(5-1)=N

48÷4=N (last step)

12=N (value of N)

Ans: B

Q5. Ans: D

6 0
3 years ago
Can you guys help me? The question is in the image
Ganezh [65]
Ugh can I see the fulll question
6 0
3 years ago
Read 2 more answers
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