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4 years ago

Write 19 3/4 as a decimal number

Mathematics

2 answers:

Aliun [14]4 years ago

5 0

Answer:

19.75

Step-by-step explanation:

1/4=0.25

2/4=0.50

3/4=0.75

so 0.75+19=19.75

KatRina [158]4 years ago

3 0

Answer:

19.75

Step-by-step explanation:

Since 19 is a whole number It'll be before the decimal point. If you take ¾ and put it into a decimal, You will get 0.75

Add the two together

19.00 + 0.75 = 19.75

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On #10 i need help to solve this. please and thank you.

valina [46]

10a. $f(x) = x - 4$
 $h(x) = \sqrt{x - 5}$
 $(f - h)(6) = (6 - 4) - (\sqrt{6 - 5})$
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10b. $f(x) = x - 4$
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 $(f * g)(x) = \frac{x - 4}{x - 3}$
 Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
 Interval Notation: (3 < x < 3), (3 > x > 3)

10c. $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt{x - 5}$
 $(g * h)(x) = (\frac{1}{x - 3})(\sqrt{x - 5})$
 $(g * h)(x) = \frac{\sqrt{x - 5}}{x - 3}$

10d. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt[3]{x - 7}$
 $h(x) = (f * g)(x)$
 $\sqrt[3]{x - 7} = (x - 4)(\frac{1}{x - 3})$
 $\sqrt[3]{x - 7} = \frac{x - 4}{x - 3}$
 $(\sqrt[3]{x - 7})^{3} = (\frac{x - 4}{x - 3})^{3}$
 $x - 7 = \frac{(x - 4)^{3}}{(x - 3)^{3}}$
 $(x - 3)^{3}(x - 7) = (x - 4)^{3}$
 $(x^{3} - 9x^2 + 27x + 27)(x - 7) = (x^{3} - 12x^{2} + 48x - 64)$
 $x^{4} - 16x^{3} + 90x^{2} - 216x + 189 = x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 90x^{2} - 216x + 189 = 17x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 102x^{2} - 216x + 189 = 17x^{3} + 48x - 64$
 $x^{4} + 102x^{2} + 189 = 17x^{3} + 264x - 64$
 $x^{4} + 102x^{2} + 253 = 17x^{3} + 264x$
 $x^{4} - 17x^{3} + 102x^{2} - 264x + 253 = 0$
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2(z - 5) + (z - 8) =

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