Use this equation: Amount after years=Initial investment*(1+Interest rate/time compounded yearly)^number of years*times compounded yearly
So A=25,000(1+.095/1)^8*1
Simplify
A=25000(1.095)^8
Simplify
A=25000(2.07)
Solve
A=$51,671.73
This equation can be used for all problems of this type.
Answer: A (-7,-4)
Step-by-step explanation:
Took the same test
Answer: a) -24
b) 
c) 4
Step-by-step explanation:
a) To determine the value of (fg)', use the product rule of derivative, i.e.:
(fg)'(x) = f'(x)g(x) + f(x)g'(x)
(fg)'(5) = f'(5)g(5) + f(5)g'(5)
(fg)'(5) = 6(-5) + 3(2)
(fg)'(5) = -24
b) The value is given by the use of the quotient rule of derivative:
![(\frac{f}{g})'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bf%7D%7Bg%7D%29%27%28x%29%3D%5Cfrac%7Bf%27%28x%29g%28x%29-f%28x%29g%27%28x%29%7D%7B%5Bg%28x%29%5D%5E2%7D)
![(\frac{f}{g})' (5)=\frac{f'(5)g(5)-f(5)g'(5)}{[g(5)]^2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bf%7D%7Bg%7D%29%27%20%285%29%3D%5Cfrac%7Bf%27%285%29g%285%29-f%285%29g%27%285%29%7D%7B%5Bg%285%29%5D%5E2%7D)


c) ![(\frac{g}{f})'(5)=\frac{g'(5)f(5)-g(5)f'(5)}{[f(5)]^{2}}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bg%7D%7Bf%7D%29%27%285%29%3D%5Cfrac%7Bg%27%285%29f%285%29-g%285%29f%27%285%29%7D%7B%5Bf%285%29%5D%5E%7B2%7D%7D)



When you have a question that comes to no solution that means when you went to solve the problem they canceled out to 0.