One positive number is 2 less than another. The sum of their squares is 34. What is the smaller number?

Mathematics

1 answer:

Viktor [21]2 years ago

3 0

Answer:
The smaller number is 3. The number 3 squared is 9, plus the other number 5 squared, which is 25. when you add them, you get 34

Step-by-step explanation:
x = first number
y = second number
a. x+2 = y
b. x^2 + y^2 = 34
Replace y from equation a into equation b:
x^2 + (x+2)^2 = 34
Expand it
x^2 + x^2 + 4x + 4 = 34
2*x^2 + 4x = 30
2x^2 + 4x - 30=0
solving x:
x = -5 and x =3 , it says it is a positive number, then it is x is 3
and the second number, y = x + 2
y = 5
Lets test it!
3^2 + 5^ 2 = 9 + 25 = 34

You might be interested in

A company has 875 employees. "Half - Price Wednesday," 64% of the employees eat lunch at the company cafeteria. How many employe

Vika [28.1K]

875 × .64= 560

answer: 560 employees eat lunch at the cafeteria on Wednesday.

4 0

3 years ago

Read 2 more answers

Choose the correct translation for the given statement.

Xelga [282]

Answer:

x > 10

Step-by-step explanation:

It must exceed ten.

Exceed: be greater

Solution: x > 10

8 0

2 years ago

Read 2 more answers

Help. Please. Thank You.

GenaCL600 [577]

Answer:

$(A)\ a=-6;b=4\\\\ (B)\ a=6;b=-4$

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+c$

Where "m" is the slope and "c" is the y-intercept.

By definition:

1. If the lines of the System of equations are parallel (whrn they have the same slope), the system has No solutions.

2. If the they are the same exact line, the System of equations has Infinite solutions.

(A) Let's solve for "y" from the first equation:

$3x-2y=-1\\\\-2y=-3x-1\\\\y=\frac{3}{2}x+\frac{1}{2}$

You can notice that:

$m=\frac{3}{2}\\\\c=\frac{1}{2}$

In order make that the System has No solutions, the slopes must be the same, but the y-intercept must not. Then, the values of "a" and "b" can be:

$a=-6\\\\b=4$

Substituting those values into the second equation and solving for "y", you get:

$-6x+4y=-2\\\\4y=6x-2\\\\y=\frac{6}{4}x-{2}{4}\\\\y=\frac{3}{2}x-\frac{1}{2}$

You can idenfity that:

$m=\frac{3}{2}\\\\c=-\frac{1}{2}$

Therefore, they are parallel.

(B) In order make that the System has Infinite solutions, the slopes and the y-intercepts of both equations must be the same. Then, the values of "a" and "b" can be:

$a=6\\\\b=-4$