Answer:
average acceleration = 6 
Explanation:
Recall that the average acceleration 
is defined by the change in velocity from an initial velocity 
, to a final velocity 
over the time (t) it took that change to happen. Then, in mathematical terms this is:
with our information this becomes:
Answer: C
Explanation: You heat the milk first then add the ingredients
Using the equations of kinematics, we obtain the following results;
- Maximum height of the cannonball = 59 m
- Velocity with which the ball strikes the building = 24 m/s
- Total time of flight of the cannonball = 7 secs
<h3>What is the maximum height?</h3>
The maximum height is the height that was attained by the projectile. In this case, we have the fact that the projectile was fired vertically upwards with a speed of 34.0m/s. On the descent, the cannonball lands on top of a 30.0m tall building.
1) The maximum height could be obtained from;
v^2 = u^2 -2gh
v = final velocity ( 0 m/s at the maximum height)
u = initial velocity = 34.0m/s
g = acceleration due to gravity = 9.8 m/s^2
h = maximum height attained
Since v = 0 m/s
u^2 = 2gh
h = u^2/2g
h = (34)^2/ 2 * 9.8
h = 1156/19.6
h = 59 m
2) Given that the distance covered from the maximum height to the top of the building = 59 m - 30 m = 29 m
v^2 = u^2 + 2gh
In this case, the initial velocity is zero because the cannonballs dropped from a height
v^2 = 2gh
v = √2gh
v = √2 * 9.8 * 29
v = 24 m/s
Given that;
v = u - gt
v = 0 m/s when the cannon ball is projected upwards;
u = gt
t = u/g
t = 34.0m/s/9.8 m/s^2
t = 3.5 secs
The total time spent in air = 2(3.5 secs) = 7 secs
Learn more about kinematics:brainly.com/question/7590442
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Answer:
the radio can tune wavelengths between 1.88 and 5.97 m
Explanation:
The signal that can be received is the one that is in resonance as the impedance of the LC circuit.
X = X_c - X_L
X = 1 / wC - w L
at the point of resonance the two impedance are equal so their sum is zero
X_c = X_L
1 / wC = w L
w² = 1 / CL
w = 
let's look for the extreme values
C = 1 10⁻¹² F
w = 
w = 
w = 10⁹ rad / s
C = 10 10⁻¹² F
w = 
Ra 1/10 10-12 1 10-6
w = 
Ra 0.1 1018
w = 0.316 10⁹ rad / s
Now the angular velocity and the frequency are related
w = 2π f
f = w / 2π
the light velocity is
c = λ f
λ = c / f
we substitute
λ = c 2π/w
we calculate the two values
C = 1 pF
λ₁ = 3 10⁸ 2π / 10⁹
λ₁= 18.849 10⁻¹ m
λ₁ = 1.88 m
C = 10 pF
λ₂ = 3 10⁸ 2π / 0.316 10⁹
λ₂ = 59.65 10⁻¹ m
λ₂ = 5.97 m
so the radio can tune wavelengths between 1.88 and 5.97 m
Heck yeah i'll follow!!!!!!
