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Lina20 [59]
3 years ago
8

A gas-powered lawnmower is rated at 98 db. how many times more intense is the sound of this mower than that of an electric-power

ed mower rated at 70 db?
Physics
1 answer:
givi [52]3 years ago
6 0
The gas- powered mower is

(98dB - 70dB) = 28 dB louder.

28 dB = 10^2.8

= 631 times as much sound power.
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because each row increases in atomic mass by a specific number, so anything over five is in the second row.

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The distance between a speaker and a listener is 8.0 m. Determine the frequency of the sound wave if exactly 20 waves are formed
dmitriy555 [2]

The frequency of the wave is 6800 Hz

<u>Explanation:</u>

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Which of the given will facilitate a normal Diels–Alder reaction?
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D

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3 years ago
What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of −25.0 nc? g?
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To calculate the force between two negative charges, we use the formula which is given by the Coulomb`s Law as

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Given  q_{1} =q_{2} =-25 nC=-25\times 10^{-9}C and  r=8 cm=8\times10^{-2} m.

Substituting these values in above formula we get,

F= 8.99\times 10^9 N m^2/C^2\frac{(-25\times 10^{-9}C)(-25\times 10^{-9}C)}{(8\times10^{-2} m)^2} \\\\\ F= 877929.7\times 10^{-9}  N\\\\F=8.8\times10^{-4}N

Thus, the repulsive force between two pith balls is 8.8\times10^{-4}N.

7 0
3 years ago
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