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Lina20 [59]
3 years ago
8

A gas-powered lawnmower is rated at 98 db. how many times more intense is the sound of this mower than that of an electric-power

ed mower rated at 70 db?
Physics
1 answer:
givi [52]3 years ago
6 0
The gas- powered mower is

(98dB - 70dB) = 28 dB louder.

28 dB = 10^2.8

= 631 times as much sound power.
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In the vertical jump, an athlete starts from crouch and jumps upward to reach as high as possible. Even the best athletes spend
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The ratio of the time he is above ymax /2 to the time it takes him to go from the floor to that height = 0.707

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The mathematical derivation and steps is as shown in the attached file.

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A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick tog
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The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

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mass of the first cart, m₁ = 2 kg

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mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

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2 x 3 + 0 = v(2 + 4)

6 = 6v

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I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

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I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

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A 29.0 kg beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
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The vertical component of force exerted by the hi.nge on the beam will be,142.10N.

To find the answer, we need to know more about the tension.

<h3>How to find the vertical component of the force exerted by the hi.nge on the beam?</h3>
  • Let's draw the free body diagram of the system.
  • To find the vertical component of the force exerted by the hi.nge on the beam, we have to balance the total vertical force to zero.

                      F_V+T sin\alpha -mg=0\\F_V=mg-Tsin\alpha \\

  • To find the answer, we have to find the tension,

                     Tlsin\alpha - mg\frac{l}{2}sin\beta =0\\ \\Tlsin\alpha = mg\frac{l}{2}sin\beta\\\\Tsin57=\frac{mg}{2}sin90\\\\T=\frac{mg}{2sin57} =169.43N

  • Thus, the vertical component of the force exerted by the hi.nge on the beam will be,

                F_V=(29*9.8)-(169.43*sin57)=142.10N

Thus, we can conclude that, the vertical component of force exerted by the hi.nge on the beam will be,142.10N.

Learn more about the tension here:

brainly.com/question/28106868

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