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Rufina [12.5K]
3 years ago
10

The tension in the string of a simple pendulum is:

Physics
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

D. None of the above

Explanation:

There are only two forces acting on a pendulum:

- The force of gravity (downward)

- The tension in the string

We can consider the axis along the direction of the string: here we have the tension T, acting towards the pivot, and the component of the weight along this direction, acting away from the pivot. Their resultant must be equal to the centripetal force, so we can write:

T-mg cos \theta = m\frac{v^2}{r}\\T=m\frac{v^2}{r}+mg cos \theta

where

T is the tension in the string

\theta is the angle between the tension and the vertical

m is the mass

g is the acceleration of gravity

v is the speed of the pendulum

r is the length of the string

From the formula we see that the value of the tension, T, depends only on the value of v (the speed) and \theta, the angle. We notice that:

- Since \theta and v constantly change, T must change as well

- At \theta=0^{\circ} (equilibrium position), cos \theta=1 (maximum value), and also the speed v is maximum, so the tension has the maximum value at the equilibrium position

- For \theta increasing, the cos \theta decreases and the speed v decreases as well, so the tension T decreases: this means that the value of the tension will be minimum in the extreme positions.

So the correct answer is D. None of the above

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The correct choice is

B. sublimation, then condensation

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condensation is the process where gas is converted into liquid on cooling.

here iodine gas is being converted into droplets on reducing the temperature. hence this is condensation.


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Itzel travels south 4 miles and then goes east 2 miles and then north 10 miles. What is her displacement? Round your answer to t
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The displacement of Itzel according to the question is 6.3 miles SW

Displacement is defined as the distance moved by a body in a specified direction

Find the diagram attached

From the diagram given, we can see that AB is the displacement

To get the length AB, we will have to use the Pythagoras theorem:

AB^2=2^2+ 6^2\\AB^2 ^2=4+36\\AB^2=40\\AB=\sqrt{40}\\AB= 6.3 miles\\

From the diagram, we can also se that the direction of the displacement in the South West direction.

Hence the displacement of Itzel according to the question is 6.3 miles SW

Learn more here: brainly.com/question/19108075

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Interdependence between plants and animals<br>​
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plants depend on animals for CO2 (to use during photosynthesis) while animals depend on plants for food (consumation)

Explanation:

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A ball has a mass of 1.5kg and is thrown straight up with a speed of 60m/s, what is the ball’s momentum:
madam [21]

Answer:

Assumption: the air resistance on this ball is negligible. Take g = 10\; \rm m \cdot s^{-2}.

a. The momentum of the ball would be approximately 60\;\rm kg \cdot m \cdot s^{-1} two seconds after it is tossed into the air.

b. The momentum of the ball would be approximately \rm \left(-45\; \rm kg \cdot m \cdot s^{-1}\right) three seconds after it reaches the highest point (assuming that it didn't hit the ground.) This momentum is smaller than zero because it points downwards.

Explanation:

The momentum p of an object is equal its mass m times its velocity v. That is: \vec{p} = m \cdot \vec{v}.

Assume that the air resistance on this ball is negligible. If that's the case, then the ball would accelerate downwards towards the ground at a constant g \approx -10\; \rm m \cdot s^{-2}. In other words, its velocity would become approximately 10\; \rm m \cdot s^{-1} more negative every second.

The initial velocity of the ball is 60\; \rm m \cdot s^{-1}. After two seconds, its velocity would have become 60\;\rm m \cdot s^{-1} + 2\; \rm s \times \left(-10\;\rm m \cdot s^{-1}\right) = 40\; \rm m \cdot s^{-1}. The momentum of the ball at that time would be around p = m \cdot v \approx 60\; \rm kg \cdot m \cdot s^{-1}.

When the ball is at the highest point of its trajectory, the velocity of the ball would be zero. However, the ball would continue to accelerate downwards towards the ground at a constant g \approx -10\; \rm m \cdot s^{-2}. That's how the ball's velocity becomes negative.

After three more seconds, the velocity of the ball would be 0\; \rm m \cdot s^{-1} + 3\; \rm s \times \left(-10\; \rm m \cdot s^{-2}\right) = -30 \; \rm m \cdot s^{-1}. Accordingly, the ball's momentum at that moment would be p = m \cdot v \approx \left(-45\; \rm kg \cdot m \cdot s^{-1}\right).

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